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3 years ago

Which property can be justified using the ratios in triangle XYZ ?

Mathematics

2 answers:

Alenkasestr [34]3 years ago

6 0

The correct answer is B.

Determine and recall first the trigonometric functions:

Sin A = Opposite/Hypotenuse
Cos A = Adjacent/Hypotenuse
Tangent = Opposite/Adjacent

If for example we try to take an angle, for example the Y, then Y is opposite Y. The Hypotenuse will be the longer side which is going to denoted by X and the next side will be Adjacent which will be denoted by Z.

Use this test to answer:

Sin Y = Y/X

where:

Y = opposite
X = hypotenuse

Cos (90 - y) = cos (90 - 50) = cos 40

where Z = 40
we look for cos Z = Y/X

Therefore,

Sin Y = Cos (90 - Y)

MatroZZZ [7]3 years ago

6 0

The previous answer is correct. There are 2 question that look the ecaxt same. Yet are different. The answer is indeed B

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Five friends want to rent a go-cart track that costs $100. Each friend intends to contribute the same about.

Inessa [10]

Just divide $100 by 5. 100 divided by 5 = $20 each.

6 0

3 years ago

1400000000000000000000km in scientific notation

viva [34]

1 400 000 000 000 000 000 000 km = 1.4 * 10^21 km

8 0

3 years ago

The average summer temperature in Anchorage is 69°F. If the daily temperature is normally distributed with a standard deviation

mafiozo [28]

Answer:

81.85%

Step-by-step explanation:

Given :

The average summer temperature in Anchorage is 69°F.

The daily temperature is normally distributed with a standard deviation of 7°F .

To Find:What percentage of the time would the temperature be between 55°F and 76°F?

Solution:

Mean = $\mu = 69$

Standard deviation = $\sigma = 7$

Formula : $z=\frac{x-\mu}{\sigma}$

Now At x = 55

$z=\frac{55-69}{7}$

$z=-2$

At x = 76

$z=\frac{76-69}{7}$

$z=1$

Now to find P(55<z<76)

P(2<z<-1)=P(z<2)-P(z>-1)

Using z table :

P(2<z<-1)=P(z<2)-P(z>-1)=0.9772-0.1587=0.8185

Now percentage of the time would the temperature be between 55°F and 76°F = $0.8185 \times 100 = 81.85\%$

Hence If the daily temperature is normally distributed with a standard deviation of 7°F, 81.85% of the time would the temperature be between 55°F and 76°F.

7 0

3 years ago

A certain radioactive isotope has leaked into a small stream. Three hundred days after the leak, 3% of the original amount of t

sesenic [268]

If the half-life is t, then every t days, the amount of the radioactive isotope will be cut in half.
(1/2)^(number of half-lives) = 3%
number of half-lives = ln(0.03) / ln(0.5)
This gives the number of half-lives as 5.06.
Then 300 days = (5.06)(length of 1 half-life)
length of 1 half-life = 300 / 5.06 = 59.29 days

6 0

3 years ago

A card is picked from a standard deck of 52 cards. Determine the odds against and the odds in favor of selecting a red face card

timama [110]

<h3>The probability of picking a red face card from the deck is $(\frac{3}{26} )$ </h3><h3>The probability of NOT picking a red face card from the deck is $(\frac{23}{26} )$ </h3>

Step-by-step explanation:

The total number of cards in the deck = 52

The total number of red( Diamond + Hearts) face cards in the given deck

= 2 Red Queens + 2 Red jacks + 2 Red kings = 6 cards

Let E : Event of picking a red face card from the deck

Now , P( any event) = $\frac{\textrm{The number of favorable observations}}{\textrm{Total number of observations}}$

So, here P(Picking a red face card) = $\frac{\textrm{The number of red face cards}}{\textrm{Total number of cards}} = (\frac{6}{52} ) = (\frac{3}{26})$

Hence, the probability of picking a red face card from the deck is $(\frac{3}{26} )$

Now, as we know P (any event NOT A) = 1 - P(any event A)

So, P(NOT Picking a red face card) = 1 - P(Picking a red face card)

$= 1 - (\frac{3}{26} ) = \frac{26-3}{26} = (\frac{23}{26})$

Hence, the probability of NOT picking a red face card from the deck is $(\frac{23}{26} )$

8 0

3 years ago