81000 would be your answer
Answer:
![f(x)=5\sin(\pi x)](https://tex.z-dn.net/?f=f%28x%29%3D5%5Csin%28%5Cpi%20x%29)
This is one possibility fitting the criteria.
Step-by-step explanation:
I was thinking about using the sine curve because we have that it starts at
and not
. The factor of 5 came from the amplitude.
So we know so far our function looks like this
.
However the inside will be effected since the period is 2.
has a period of
.
has a period of
.
We want
to have a period of 2 so we want to solve
.
So multiply both sides by b:
![2\pi=2b](https://tex.z-dn.net/?f=2%5Cpi%3D2b)
Divide both sides by 2:
![\frac{2\pi}{2}=b](https://tex.z-dn.net/?f=%5Cfrac%7B2%5Cpi%7D%7B2%7D%3Db)
.
So the function we have from the given information is:
![f(x)=5\sin(\pi x)](https://tex.z-dn.net/?f=f%28x%29%3D5%5Csin%28%5Cpi%20x%29)
Answer:
x=3
Step-by-step explanation:
using the pythagorean theorem, c^2=a^2+b^2
5^2=x^2+4^2, x=3
![b = h - 1](https://tex.z-dn.net/?f=b%20%3D%20h%20-%201)
![A = \frac 1 2 b h = \frac 1 2 (h-1) h](https://tex.z-dn.net/?f=A%20%3D%20%5Cfrac%201%202%20b%20h%20%3D%20%5Cfrac%201%202%20%28h-1%29%20h)
![15 = \frac 1 2 (h-1)(h)](https://tex.z-dn.net/?f=15%20%3D%20%5Cfrac%201%202%20%28h-1%29%28h%29)
![30 = h^2 - h](https://tex.z-dn.net/?f=30%20%3D%20h%5E2%20-%20h)
![h^2 - h - 30 =0](https://tex.z-dn.net/?f=%20h%5E2%20-%20h%20-%2030%20%3D0%20)
![(h-6)(h+5)=0](https://tex.z-dn.net/?f=%28h-6%29%28h%2B5%29%3D0)
![h=6 \textrm{ or } h=-5](https://tex.z-dn.net/?f=h%3D6%20%5Ctextrm%7B%20or%20%7D%20h%3D-5)
We can reject the negative height
Answer: 6 meters, second choice
Answer:
x=6+2y
Step-by-step explanation: