Solve for y: 6x-2y= -8

Steph makes 90 % 90%90, percent of the free throws she attempts. She is going to shoot 3 33 free throws. Assume that the results

zmey [24]

Using the binomial distribution, it is found that there is a 0.027 = 2.7% probability that he makes exactly 1 of the 3 free throws.

For each free throw, there are only two possible outcomes, either he makes it, or he misses it. The results of free throws are independent from each other, hence, the binomial distribution is used to solve this question.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

In this problem:

He makes 90% of the free throws, hence $p = 0.9$ .

He is going to shoot 3 free throws, hence $n = 3$ .

The probability that he makes exactly 1 is P(X = 1), hence:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{3,1}.(0.9)^{1}.(0.1)^{2} = 0.027$

0.027 = 2.7% probability that he makes exactly 1 of the 3 free throws.

To learn more about the binomial distribution, you can take a look at brainly.com/question/24863377

3 0

2 years ago

A university interested in tracking its honors program believes that the proportion of graduates with a GPA of 3.00 or below is

insens350 [35]

Answer:

The value of the test statistic and its associated p-value at the 5% significance level are -1.54 and 0.9382, respectively.

Step-by-step explanation:

A university interested in tracking its honors program believes that the proportion of graduates with a GPA of 3.00 or below is less than 0.16.

This means that the null hypothesis is:

$H_{0}: p \geq 0.16$

Testing this hypothesis, means that the alternate hypothesis is:

$H_{a}: p > 0.16$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

0.16 is tested at the null hypothesis:

This means that $\mu = 0.16, \sigma = \sqrt{0.16*0.84}$

In a sample of 200 graduates, 24 students have a GPA of 3.00 or below.

This means that $n = 200, X = \frac{24}{200} = 0.12$

Value of the test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{0.12 - 0.16}{\frac{\sqrt{0.16*0.84}}{\sqrt{200}}}$

$z = -1.54$

Pvalue:

The pvalue is the probability of finding a sample mean above 0.12, which is 1 subtracted by the pvalue of z = -1.54.

Looking at the z-table, z = -1.54 has a pvalue of 0.0618

1 - 0.0618 = 0.9382

The value of the test statistic and its associated p-value at the 5% significance level are -1.54 and 0.9382, respectively.

6 0

3 years ago

Is p=2.5(600-500R)+-500 and p=-1250R+1000 a linear or nonlinear function? Explain.

ANEK [815]

Answer:

you dumb ...................

Step-by-step explanation:

4 0

3 years ago

Andre is preparing for the school play and needs to paint the cardboard castle backdrop that measures feet by 6 feet.

7nadin3 [17]

Answer:

a. 85.5 sq ft

b. 3 bottles

Step-by-step explanation:

a. The cardboard is rectangular in shape. How much he needs to paint is the same as the cardboard that he needs to paint.

The area of a rectangle is given as:

A = L * B

where L = length and B = breadth

Therefore, the area of the cardboard having dimensions 14 1/4 feet by 6 feet is:

A = 14 1/4 * 6

A = 57 / 4 * 6 = 85.5 sq feet

He needs to paint 85.5 sq feet of the cardboard.

b. On bottle of paint covers 40 sq feet. The number of bottles he will need for his backdrop will be the area he needs to paint divided by the amount of paint that can cover 40 sq feet:

85.5 / 40 = 2.14

Since the number of bottles he will need is a whole number and its greater than 2, then it must be 3.

To paint the entire cardboard, he must have 3 bottles of paint.

8 0

3 years ago

What is a sextant and how is it used?

Elan Coil [88]

A sextant is a doubly reflecting navigation instrument that measures the angular distance between two visible objects. The primary use of a sextant is to measure the angle between an astronomical object and the horizon for the purposes of celestial navigation.

The estimation of this angle, the altitude, is known as sighting or shooting the object, or taking a sight. The angle and the time when it was measured, can be used to calculate a position line on a nautical or aeronautical chart. For example; sighting the Sun at noon or Polaris at night (in the Northern Hemisphere) to estimate latitude. Sighting the height of a landmark can give a measure of distance off and held horizontally.

A sextant can measure angles between objects for a position on a chart. A sextant can also be used to measure the lunar distance between the moon and another celestial object (such as a star or planet) in order to determine Greenwich Mean Time and hence longitude.

Hope this helps!

~ ShadowXReaper069

7 0

3 years ago