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strojnjashka [21]
2 years ago
11

What is the trigonometric ratio for cosn? enter your answer, as a simplified fraction, in the boxes. $$ triangle l m n with righ

t angle m. l m equals 15. l n equals 39. m n equals 36.
Mathematics
1 answer:
hjlf2 years ago
3 0

The trigonometric ratio will be Cos(n)=12/13

<h3>What will be the trigonometry ratio?</h3>

Given is a Right triangle LMN with right angle at M i.e. angle M = 90 degrees.

Given are the sides LM = 15, MN = 36, and LN = 39.

It says to find cos(n) = ?

So opposite side would be LM, adjacent side would be MN, and LN is the hypotenuse.

We know that the cosine ratio is given by :-

Cos(n)=\dfrac{adjacent}{Hypotenuse}

Cos(n)=\dfrac{MN}{LN}

Cos(n)=\dfrac{36}{39}

Cos(n)=\dfrac{12}{13}

Hence the required ratio will be   Cos(n)=\dfrac{12}{13}

To know more about trigonometry, follow

trigonometry

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The answer is C hope I helped
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3 years ago
Sally Reynolds sells real estate along the coastal area of Northern California. Below are her total annual commissions between 2
tatiyna

Answer:

Mean = $229.32

Median = $231.15

Mode = $268.4

Step-by-step explanation:

Mean = the average.

The average is the sum of variables divided by the number of variables.

x = each variable

N = number of variables = 11

Average = (Σx)/N = (236.09 + 204.43 + 253.82 + 268.4 + 231.15 + 205.7 + 262.18 + 162.77 + 268.4 + 224.45 + 205.17)/11

Mean = 2522.56/11 = $229.32

b) Median is the value that falls at the middle of the data set if all the variables are arranged in ascending or descending order.

So, to find the Median, we first arrange the variables in ascending order.

162.77

204.43

205.17

205.70

224.45

231.15

236.09

253.82

262.18

268.4

268.4

Since there are 11 variables, the Median is the number that falls at the middle of the distribution, that is, at the sixth position.

Median = $231.15

c) Mode is the number that appears the most in a distribution.

In this distribution, only 268.4 appears more than once.

Hence, the more is $268.4

8 0
3 years ago
4(3x^2y^4)^3 / (2x^3y^5)^4
tatyana61 [14]

Solving the expressions  \frac{4(3x^2y^4)^3}{(2x^3y^5)^4} we get \frac{27}{4x^{6}y^{8}}

Step-by-step explanation:

We need to Solve the expression: \frac{4(3x^2y^4)^3}{(2x^3y^5)^4}

Solving:

\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}

=\frac{4(3^3x^6y^{12})}{(2^4x^{12}y^{20})}\\=\frac{4(27x^6y^{12})}{(16x^{12}y^{20})}\\=\frac{108x^6y^{12}}{16x^{12}y^{20}}

Applying exponent rule: \frac{x^a}{x^b}=x^{a-b}

=\frac{108x^{6-12}y^{12-20}}{16}\\=\frac{27x^{-6}y^{-8}}{4}

Another exponent rule says: x^{-a}=\frac{1}{x^a}=

=\frac{27}{4x^{6}y^{8}}

So, solving the expressions  \frac{4(3x^2y^4)^3}{(2x^3y^5)^4} we get \frac{27}{4x^{6}y^{8}}

Keywords: Solving Exponents  

Learn more about Solving Exponents at:

  • brainly.com/question/13174260
  • brainly.com/question/13174254
  • brainly.com/question/13174259

#learnwithBrainly

8 0
3 years ago
If you flip the five coins, and the probability of one coin being "tails" is 0.50, what is the probability of getting "tails" on
jenyasd209 [6]

Answer: 0.03125

Step-by-step explanation:

We know that the probability of getting a tail , we toss a fair coin = 0.5

Given : Total number of trials = 5

Using binomial probability formula :

P(x)=^nC_xp^x(1-p)^{n-x}, where P(x) is the probability of getting success in x trails, n is total number of trials and p is the probability of getting success in each trial.

The probability of getting "tails" on all five coins :_

P(x=5)=^5C_5(0.5)^5(1-0.5)^0=(1)(0.5)^5=0.03125

Hence,  the probability of getting "tails" on all five coins =0.03125

8 0
3 years ago
What is the approximate area of a circle with a radius of 10 in?
yKpoI14uk [10]

<em></em>\huge\boxed{\textsf{A.}\ 78.5\ \text{in}^2}

<em></em>

<em>Correction to your question text: diameter, not radius.</em>

The area of a circle is given by:

A=\pi r^2

The radius is half of the diameter.

A=\pi\cdot\left(\dfrac{10}{2}\right)^2

Substitute and solve.

\begin{aligned}A&=\pi\cdot\left(\frac{10}{2}\right)^2\\&=\pi\cdot5^2\\&=\pi\cdot25\\&\approx\boxed{78.5}\end{aligned}

5 0
2 years ago
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