Answer:What are the equivalence classes of the equivalence relations in Exercise 3? A binary relation defined on a set S is said to be equivalence relation if it is reflexive, symmetric and transitive. An equivalence relation defined on a set S, partition the set into disjoint equivalence classes
Answer:
1. 0.6
2. 0.25
Step-by-step explanation:
because math
Answer:
208
Step-by-step explanation:
Given that;
Given that;
y= a(1 - b)^t
Where;
wherein y is the final amount, a is the original amount, b is the decay factor, and x is the amount of time that has passed.
To obtain the constant b,
y= ae^-bt
Substituting values;
1000 = 3000 e^-b(50)
1000/3000 = e^b(50)
0.33 = e^b-(50)
ln (0.33) = ln(e^b(-50))
-1.1 = -50b
b= 1.1/50
b= 0.022
After two hours or 120 minutes;
y= 3000(1 - 0.022)^120
y= 207.8661772
y= 208
I think the answer is
0.32
Answer:
Sample Space = {A, B, C, D, E, F}.
Sample space for choosing C to F = {C, D, E, F}.
Step-by-step explanation:
All six letters are included in the first set of possible outcomes.
Four letters (C to F) are included in the second set of possible outcomes.
