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NeTakaya
3 years ago
12

If a rooster laid 13 eggs and the farmer took eight of them and then another rooster laid 12 eggs and four of them were rotten,

how many of the eggs were left?
Mathematics
2 answers:
earnstyle [38]3 years ago
5 0
There were 13 eggs left
Art [367]3 years ago
3 0
1st rooster:
13-8=5

2nd rooster:
12-4=8

8+5=13

13 eggs left

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If P*Q = PxQ - 7,<br> what is 9*5?
ycow [4]

Given problem:

 What is 9*5;

 The formula P*Q  = P x Q  - 7;

To  find 9*5, simply make P = 9 and Q = 5

Input into the equation and solve;

   

   P*Q  = P x Q  - 7    =   9 x 5 - 7

                                 = 45 - 7

                                 = 38

The solution to this problem is 38.

4 0
3 years ago
Please help, will mark brainliest
dem82 [27]

Answer:

34.6= b

Step-by-step explanation:

a^2 + b^2 =c^2

13^2+b^2= 37^2

169+b^2= 1369

-169            -169

b^2 = 1200

\sqrt{b} = \sqrt{1200\\

b= 34.6

5 0
3 years ago
Read 2 more answers
Find the area of the triangle with the given vertices. Use the fact that the area of the triangle having u and v as adjacent sid
Gnom [1K]

Answer:

The area of the triangle is A=\sqrt{\frac{4027}{2}}

Step-by-step explanation:

Using the fact that the area of the triangle having u and v as adjacent sides is given by

A=\frac{1}{2}||{\bf u} \times {\bf v} ||

We know that we want to take a cross product to compute the area of the triangle, but we need to be careful because it doesn't make sense if we take the cross product of points.

The first step is to build some vectors that describe this triangle.

According with the graph we can build the vectors:

{\bf AB} and {\bf AC}

The vector {\bf AB} is the difference of point B minus point A

{\bf AB}=(5-3,5-5,0-9)=(2,0,-9)

and the vector {\bf AC} is the difference of point C minus point A

{\bf AC}=(-4-3,0-5,2-9)=(-7,-5,-7)

Next we need to find the cross product of this vectors.

{\bf AB} \times {\bf AC}=\begin{pmatrix}2&0&-9\end{pmatrix}\times \begin{pmatrix}-7&-5&-7\end{pmatrix}

This is the definition of cross product of two vectors in space:

Let {\bf u} = u_1{\bf i}+u_2{\bf j}+u_3{\bf k} and {\bf v} = v_1{\bf i}+v_2{\bf j}+v_3{\bf k} be vectors in space. The cross product of {\bf u} and {\bf v} is the vector

{\bf u} \times {\bf v}=(u_2v_3-u_3v_2){\bf i}-(u_1v_3-u_3v_1){\bf j}+(u_1v_2-u_2v_1){\bf k}

Applying this definition we get

{\bf AB} \times {\bf AC}=\begin{pmatrix}2&0&-9\end{pmatrix}\times \begin{pmatrix}-7&-5&-7\end{pmatrix}

\begin{pmatrix}0\cdot \left(-7\right)-\left(-9\left(-5\right)\right)&-9\left(-7\right)-2\left(-7\right)&2\left(-5\right)-0\cdot \left(-7\right)\end{pmatrix}\\\\\begin{pmatrix}-45&77&-10\end{pmatrix}

||{\bf AB} \times {\bf AC}||=\sqrt{(-45)^2+(77)^2+(-10)^2} \\\\||{\bf AB} \times {\bf AC}||=\sqrt{2025+5929+100}\\\\||{\bf AB} \times {\bf AC}||=\sqrt{8054}

The area of the triangle is

A=\frac{1}{2}||{\bf AB} \times {\bf AC} ||=\frac{1}{2}\sqrt{8054}=\sqrt{\frac{4027}{2}}

7 0
4 years ago
Which property do i use to solve x-10=15
Stells [14]
Add both sides by 10

x=25
3 0
4 years ago
1. It costs $3.45 to buy 3/4 lb of chopped walnuts. How much would it cost to purchase
konstantin123 [22]

Answer:

$34.50

Step-by-step explanation:

First, how many 3/4 lbs are in 7.5 lbs?

7.5 lbs = 15/2 lbs.

(15/2) / (3/4) = 10

There are 10 "3/4" lbs in 7.5 lbs.

So, if it costs $3.45 to purchase 3/4 lbs of chopped walnuts, it would cost $3.45 times 10 dollars to purchase 7.5 lbs of chopped walnuts, or $34.50.

Let me know if this helps!

5 0
3 years ago
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