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3 years ago

Help??? Can someone help me with all of them???

Mathematics

1 answer:

ArbitrLikvidat [17]3 years ago

6 0

The answer is -2,-3 :()

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If angle 0 is in quadrant I, what is the value of

Brilliant_brown [7]

Answer:

$the \: answer \: is \: c \: = - \frac{ \sqrt{14} }{5}$

Step-by-step explanation:

$\sin^{2}0 + ( \frac{ \sqrt{11} }{5} ) ^{2} = 1( \sin^{2}0 + \cos^{2} 0 = 1)$

${ \sin }^{2}0 + \frac{11}{25} = 1 \\ { \sin }^{2}0 = \frac{14}{25}$

$\sin0_{1} = - \frac{ \sqrt{14}}{5} while \sin0_{2} = \frac{ \sqrt{14} }{5}$

Therfore theta is QI
Therfore sin theta >0
$therefore \: \sin0 = \frac{ \sqrt{14} }{5}$

4 0

2 years ago

What is answer to this question ?

Semenov [28]

A its not a function

6 0

3 years ago

which of the following expresses the coordinates of the foci of the conic section shown below? (x-2)^2/4+(y+5)^2/9

elena55 [62]

Step-by-step explanation:

$\frac{(x - 2) {}^{2} }{4} + \frac{(y + 5) {}^{2} }{9} = 1$

This is the equation of the ellipse. Since the denominator is greater for the y values, we have a vertical ellipse. Remember a>b, so a

The formula for the foci of the vertical ellipse is

(h,k+c) and (h,k-c).

where c is

Our center (h,k) is (2, -5)

${c}^{2} = {a}^{2} - {b}^{2}$

Here a^2 is 9, b^2 is 4.

${c}^{2} = 9 - 4$

${c}^{2} = 5$

$c = \sqrt{5}$

So our foci is

$(2, - 5 + \sqrt{5} )$

and

$(2, - 5 - \sqrt{5} )$

6 0

2 years ago

6700 dollars is placed in an account with an annual interest rate of 8%. How much will be in the account after 24 years, to the

goldenfox [79]

Answer:

Step-by-step explanation:

The answer depends on whether the interest is simple or compound.

For simple interest:

A = 670(1 + 0.08)(24)

For compound interest

A = 670(1 + 0.08)24

5 0

3 years ago

Read 2 more answers

Can someone explain how to due this

ElenaW [278]

It’s just 5 you divide 9 into 45 and get a whole number of 5

7 0

3 years ago