F(t)=2t−3 f(7)=____ I need some help im not sure what to do here
1 answer:
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Answer:
y = -4x - 4
Step-by-step explanation:
If we have two lines in slope intercept form as
then the product of the slopes
In other words,
We have the first line as
The slope of this line is
The slope of a perpendicular line will be the negative of the reciprocal of this line
Reciprocal of 1/4 is 4
So slope of perpendicular line is -4 which implies
y = -4x + c
We have to determine c
Since the line passes through (-3, 8), plug in these values for x and y in the equation and solve for c
8 = (-4)(-3) + c
8 = 12 + c
c = -4
So the equation of the perpendicular line is y = -4x - 4 (Answer)
It is always a good idea to plot these graphs and see if they fit the data provided
The attached plot shows the two graphs and you can see they are perpendicular to each other and the perpendicular line(the answer) passes through point (-3,8)
There is a multiple zero at 0 (which means that it touches there), and there are single zeros at -2 and 2 (which means that they cross). There is also 2 imaginary zeros at i and -i.
You can find this by factoring. Start by pulling out the greatest common factor, which in this case is -x^2.
-x^6 + 3x^4 + 4x^2
-x^2(x^4 - 3x^2 - 4)
Now we can factor the inside of the parenthesis. You do this by finding factors of the last number that add up to the middle number.
-x^2(x^4 - 3x^2 - 4)
-x^2(x^2 - 4)(x^2 + 1)
Now we can use the factors of two perfect squares rule to factor the middle parenthesis.
-x^2(x^2 - 4)(x^2 + 1)
-x^2(x - 2)(x + 2)(x^2 + 1)
We would also want to split the term in the front.
-x^2(x - 2)(x + 2)(x^2 + 1)
(x)(-x)(x - 2)(x + 2)(x^2 + 1)
Now we would set each portion equal to 0 and solve.
First root
x = 0 ---> no work needed
Second root
-x = 0 ---> divide by -1
x = 0
Third root
x - 2 = 0
x = 2
Forth root
x + 2 = 0
x = -2
Fifth and Sixth roots
x^2 + 1 = 0
x^2 = -1
x = +/-
x = +/- i