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spayn [35]
3 years ago
11

How do you solve for r. -2r-5=18

Mathematics
2 answers:
lord [1]3 years ago
5 0
-2r - 5 = 18
      +5     +5
-2r = 23
/ divide both sides by -2

r = -11.5

r-ruslan [8.4K]3 years ago
3 0
The answer is r=-23/2
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Fofino [41]

The probability of senior citizens suffer from sleep disorders is

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a. The probability that a senior citizen suffers from anxiety, given that he or she has a

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P(A|B)=\frac{P(A\cap B)}{P(B)}P(A|B)=\frac{0.06}{0.09}P(A|B)=0.67

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Find an equation for the line tangent to the curve at the point defined by the given value of t. Also, find the value of d^2y/dx
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Differentiation will give you the gradient for the tangent at any point, and you use the product rule whenever a function can be thought of as two functions multiplied together.

If

f

(

x

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x

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×

h

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x

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then

f

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x

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=

g

'

(

x

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h

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x

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+

g

(

x

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h

'

(

x

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so if

y

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d

x

=

1

×

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x

+

x

×

cos

x

=

sin

x

+

x

cos

x

We know that

x

=

π

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, so the gradient is

m

=

sin

(

π

2

)

+

π

2

cos

(

π

2

)

=

1

+

π

2

×

0

=

1

Therefore, we can say that

y

=

m

x

+

c

y

=

(

1

)

x

+

c

y

=

x

+

c

So all we really need to find now is the value for

c

, the

y

intercept. We do this by working out a point

(

x

,

y

)

on the graph. We are already given that

x

=

π

2

, so

y

=

x

sin

x

=

π

2

sin

(

π

2

)

=

π

2

×

1

=

π

2

∴

(

x

,

y

)

=

(

π

2

,

π

2

)

Now we substitute this into the equation we already have for the tangent,

y

=

x

+

c

,

(

x

,

y

)

=

(

π

2

,

π

2

)

π

2

=

π

2

+

c

c

=

π

2

−

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2

=

0

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y

=

x

+

c

=

x

+

(

0

)

=

x

which means the tangent to the curve

y

=

x

sin

x

at

(

π

2

,

π

2

)

is simply

y

=

x

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3 0
3 years ago
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Tcecarenko [31]

Answer:

the second one

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48 in2 should be the answer
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Answer:

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