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2 years ago

What are the slope and the y-intercept of the linear function that is represented by the graph?

Mathematics

1 answer:

BabaBlast [244]2 years ago

7 0

The slope is 3, and the y-intercept is 9

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3x+5y = 15 find the slope of a line perpendicular to each given line

gladu [14]

Answer:

Slope = 5/3

Step-by-step explanation:

See attached image

5 0

1 year ago

What type of measurement would you use to describe the amount of water a pot can hold

notsponge [240]

The measurement you would need is litres. 1000ml = 1litre^2

4 0

3 years ago

Read 2 more answers

Please its very urgent :( Name five whole numbers that can be expressed as the difference of two perfect squares. Show the math!

Tatiana [17]

Answer:

9, 17, 3, 1600, 11

Step-by-step explanation:

Difference of two perfect squares:

$a^2-b^2=(a-b)(a+b)$

It seems that you want some

$x=a^2-b^2, x \in \mathbb{Z}_{\ge 0}$

Note: there's no official symbol for the set of whole numbers, I've already seem $\mathbb{W}, \mathbb{Z}^+$ , as well.

$5^2-4^2=25-16=9$

There are infinitely many numbers that can satisfy the condition given.

The only condition is that $a\geq b$ , once we are considering whole numbers and not integers.

$x_{1}=5^2-4^2=25-16=9$

$x_{2}=9^2-8^2=81-64=17$

$x_{3}=2^2-1^2=4-1=3$

$x_{4}=50^2-30^2=2500-900=1600$

$x_{5}=6^2-5^2=36-25=11$

3 0

2 years ago

Evaluate the limit of sequence:

mr_godi [17]

Rationalize both the numerator and denominator. Given

$\dfrac{\sqrt a-\sqrt b}{\sqrt c-\sqrt d}$

we can rationalize it by introducing conjugates of the numerator and denominator:

$\dfrac{\sqrt a-\sqrt b}{\sqrt c-\sqrt d} \cdot \dfrac{\sqrt a+\sqrt b}{\sqrt a+\sqrt b} \cdot \dfrac{\sqrt c+\sqrt d}{\sqrt c+\sqrt d} \\\\ = \dfrac{\left(\sqrt a\right)^2 - \left(\sqrt b\right)^2}{\left(\sqrt c\right)^2-\left(\sqrt d\right)^2} \cdot \dfrac{\sqrt c+\sqrt d}{\sqrt a + \sqrt b} \\\\ = \dfrac{a-b}{c-d} \cdot \dfrac{\sqrt c+\sqrt d}{\sqrt a + \sqrt b}$

Then the limit is equivalent to

$\displaystyle \lim_{n\to\infty} \frac{(n+3)-n}{(n+1)-n} \cdot \dfrac{\sqrt{n+1}+\sqrt n}{\sqrt{n+3}+\sqrt n} = 3 \lim_{n\to\infty} \dfrac{\sqrt{n+1}+\sqrt n}{\sqrt{n+3}+\sqrt n}$