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LenKa [72]
3 years ago
11

Carl owns a tile store. the tile store. Kingwood School wants to retire a hallway that is 26 feet long and 8 feet wide. What is

the number of square foot floor tile Carl will need to retire the hallway
Mathematics
1 answer:
lisov135 [29]3 years ago
7 0

Answer:

208

Step-by-step explanation:

26 x 8=208

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Pls help I don't know how to do this​
AVprozaik [17]

Answer:

Vertex, I believe.

7 0
3 years ago
The image of the polygon ABCDE reflected across the x-axis. A(-1,-1),B(0,1),C(4,2),D(6,0),E(3,-3) The vertices of the image are.
4vir4ik [10]

A reflection across the x-axis has the rule:

(x,y)→(x,-y).

Then:

  • A(-1,-1)→A'(-1,1),
  • B(0,1)→B'(0,-1),
  • C(4,2)→C'(4,-2),
  • D(6,0)→D'(6,0),
  • E(3,-3)→E'(3,3).

Answer: the vertices of the image are A'(-1,1), B'(0,-1), C'(4,-2), D'(6,0) and E'(3,3).

6 0
4 years ago
The example of a beach ball with a ping pong ball inside of it can be used to imagine the relationship between what two entities
Nookie1986 [14]

The celestial sphere and Earth is the example of a beach ball with a ping pong ball inside of it can be used to imagine the relationship between what two entities.

The heavenly sphere is what Why is this old idea still relevant today?

  • Ancient people used the celestial sphere to describe the visible universe.
  • Although our understanding of the cosmos has changed, the concept of a celestial sphere is still prevalent because it provides a straightforward perspective on the stars that is useful for navigation.

Which phrase most accurately sums up the celestial sphere?

The entire sky as seen from Earth is portrayed by the celestial sphere. Keep in mind that the celestial sphere is intended to depict the sky as it appears from our planet rather than physical reality.

Learn more about celestial sphere

brainly.com/question/13196153

#SPJ4

3 0
2 years ago
Someone please help or i’ll be failing geometry this year
Vlad [161]

Step-by-step explanation:

I don't know what constructions you were taught.

a "similar" triangle is a triangle with exactly the same angles as the other triangle, but the lengths of all sides are stretched or shortened by the same scaling factor f.

by saying 1:2 she means the second triangle should have sides with twice the lengths of the first triangle (f=2).

and the extra challenge - same basic thing. she allows you to pick one of the two triangles as reference. and then you need to draw a third triangle (again with the same angles) with the side lengths extended by the scaling factor f of 4/3.

I would draw the triangles right on top of each other with the same starting corner (let's call it A) for all 3.

we would get the triangles ABC, AMN and AXY.

the points B and C would be then halfway on AM and AN.

and M and N would then a bit before X and Y on AX and AY.

the beauty is, you only need to construct 2 sides of every new triangle down to the new endpoints. the third side is automatically scaled correctly, and you only need to connect these new endpoints.

let's assume you draw a triangle (just very simple) ABC with all side lengths being 3. so, AB=3, AC=3, BC=3.

now you draw AMN by extending AB and AC to a side length of 6 (f=2) creating M and N, and you connect M and N.

and then you can create the third triangle AXY by extending AM and AN by a factor of 4/3 to side lengths of 8 (4/3 × 6 = 8) creating new end points X and Y. and you connect X and Y.

and that is it. all 3 triangles are similar (the same angles), and all sides of a triangle have the same length ratio to the sides of the other triangle(s).

4 0
3 years ago
A rocket is launched at 85 ft./s from a launch pad that’s 28 feet above the ground. which equation can be used to determine the
3241004551 [841]

Answer:

h(t)=-16t^2+85t+28  is equation of height of rocket.

Option D is correct.

Step-by-step explanation:

Given: A rocket is launched with speed 85 ft/s from a height 28  feet.

Launching a rocket follows the path of parabola. The equation of rocket should be parabolic.

Parabolic equation of rocket is

Formula: h(t)=\dfrac{1}2gt^2+v_0t+h_0

g ⇒ acceleration due to gravity (-32 ft/s)

v ⇒ Initial velocity (v_0=85\ ft/s)

h ⇒ Initial height (h_0=28\ feet)

h(t) ⇒ function of height at any time t

Substitute the given values into formula

h(t)=\frac{1}{2}(-32)t^2+(85)t+28

h(t)=-16t^2+85t+28

D is correct.

6 0
4 years ago
Read 2 more answers
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