I got -880 , i’m not sure you can get only
positive exponents...
Answer:
523.6
Step-by-step explanation:
Following the calculation, and 3.14 for pi, the answer would be 523.6
The answer
ellipse main equatin is as follow:
X²/ a² + Y²/ b² =1, where a≠0 and b≠0
for the first equation: <span>x = 3 cos t and y = 8 sin t
</span>we can write <span>x² = 3² cos² t and y² = 8² sin² t
and then </span>x² /3²= cos² t and y²/8² = sin² t
therefore, x² /3²+ y²/8² = cos² t + sin² t = 1
equivalent to x² /3²+ y²/8² = 1
for the second equation, <span>x = 3 cos 4t and y = 8 sin 4t we found
</span>x² /3²+ y²/8² = cos² 4t + sin² 4t=1
The answer to this question would be 3d-2=31 and d=11
Start with

Separate the variables:

Integrate both parts:

Which implies

Solving for y:

Since
is itself a constant, let's rename it
.
Fix the additive constant imposing the condition:

So, the solution is
