Correct question:
The height of a right cylinder is 3 times the radius of the base. The volume of the cylinder is 242 cubic units.
Answer:
6 units
Step-by-step explanation:
Let, radius, r = x
Height, h = 3x
Volume, V = 24π
Volume of cylinder = =πr²h
24π = π * x² * 3x
24π = π* 3x³
24 = 3x³
24 / 3= x³
8 = x³
x = 2
Height, h = 3x
h = 3(2) = 6 units
This can be solve by using the average cans of each student
collected and muliply it by the total students. Since for ms. Lee has 24
students and each student collected 18 cans on average, so the total can her
class collected on average is 432 cans. For mr galveshas 21 students and
collected 25 can per syudents on average, so the total is 525 cans. So 525 –
432 = 93 more cans the class of mr galvez collected
Answer:
x = {nπ -π/4, (4nπ -π)/16}
Step-by-step explanation:
It can be helpful to make use of the identities for angle sums and differences to rewrite the sum:
cos(3x) +sin(5x) = cos(4x -x) +sin(4x +x)
= cos(4x)cos(x) +sin(4x)sin(x) +sin(4x)cos(x) +cos(4x)sin(x)
= sin(x)(sin(4x) +cos(4x)) +cos(x)(sin(4x) +cos(4x))
= (sin(x) +cos(x))·(sin(4x) +cos(4x))
Each of the sums in this product is of the same form, so each can be simplified using the identity ...
sin(x) +cos(x) = √2·sin(x +π/4)
Then the given equation can be rewritten as ...
cos(3x) +sin(5x) = 0
2·sin(x +π/4)·sin(4x +π/4) = 0
Of course sin(x) = 0 for x = n·π, so these factors are zero when ...
sin(x +π/4) = 0 ⇒ x = nπ -π/4
sin(4x +π/4) = 0 ⇒ x = (nπ -π/4)/4 = (4nπ -π)/16
The solutions are ...
x ∈ {(n-1)π/4, (4n-1)π/16} . . . . . for any integer n
Answer:
The area will be 834.38
Step-by-step explanation:
hope it helps..
