There are 90 two digit numbers
Answer:
The first 5 terms are;
-2, 2, 13,38 and 91
Step-by-step explanation:
Here, we want to write the first 5 terms of the sequence.
We already have the first term as 1
Now, we need the 2nd term
Putting two in place of n, we have ;
2f(1) + 3n
= 2(-2) + 3(2) = -4 + 6 = 2
For the 3rd term, put 3 in place of n
2f(2) + 3(3)
sine f(2) = 2, we have
2(2) + 9 = 4+ 9 = 13
For the fourth term, put 4 in place of n, we have
2f(3) + 3(4)
since f(3) = 13
we have; 2(13) + 12 = 26 + 12 = 38
For the 5th term, put 5 in place of n, we have
2f(4) + 3(5)
since f(4) = 38, we have
2(38) + 15 = 76 + 15 = 91
Answer:
the distance i believe between the points are
(1,1) , (3,3)
(7,9) , (0,3)
(1,2) , ( 3,9)
Step-by-step explanation:
650 to the nearest 100
And anything above 650 to the nearest 100 might be reading the question wrong sorry
