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vivado [14]
3 years ago
11

(-1) - (-4) using counters

Mathematics
1 answer:
lana [24]3 years ago
7 0
(-1)-(-4)
-1+4
=3
The answer is 3
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What is the value of x? I’m a bit confused. Please answer as soon as possible
Paha777 [63]

Answer: 300?

i wouldnt know bc math isnt my strong suit but i would guess : )

Step-by-step explanation:

thats ALOT of numbers!

5 0
3 years ago
Use Gauss-Jordan elimination to solve the following linear system:
Olenka [21]
-3x + 4y = -6

20x - 4y = 40
-----------------------
17x = 34

x = 2

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10 - y = 10

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the correct answer is D. (2,0)
4 0
3 years ago
Read 2 more answers
Determine if the triangles in each pair are similar. If so, create a flowchart proof, If not, explain how you know.
olga_2 [115]

Answer:

∆<em>LMN</em> ~ ∆<em>LQR</em>

Step-by-step explanation:

All you have to do is match their similar corresponding angles.

* These are congruent by the Angle-Angle Similarity Postulate, where at least two angles of both triangles are congruent, which in this case is ∠<em>L</em> [Vertical Angles Theorem] and ∠<em>Q</em> & ∠<em>M</em>. This obviously gives us our third side in each triangle, which must sum up to 180° altogether, therefore you have your answer.

I am joyous to assist you anytime.

7 0
4 years ago
Pahelp Po pls.. hina ko kase sa math hihi:,-):-)​
SIZIF [17.4K]

Step-by-step explanation:

1) C

2) B

5) C

6)D

7) D

8) B

9) Figure not clear

10) C

11) D

12) B

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5 0
2 years ago
For the sample standard deviation(s) for situations involving means, explain whether it affects the width of a confidence interv
Lisa [10]

Answer:

Affects the width of a confidence interval, as the margin of error is a function of the sample standard deviation.

Step-by-step explanation:

When we have the standard deviation for the sample, the t-distribution is used to solve the question.

It does not affect the center of the interval, which is a function only of the sample mean.

Width of a confidence interval:

The width of a confidence interval is a function of the margin of error, which is:

M = t\frac{s}{\sqrt{n}}

In which s is related to the sample standard deviation. Thus, since s and M are directly proportional, a higher standard deviation makes the interval wider, lower standard deviation makes the interval narrower, and thus, the sample standard deviation affects the the width of a confidence interval.

6 0
3 years ago
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