If sin theta = sqrt(2/2), which could not be the value of theta?
2 answers:
The solution would be like this for this specific problem:
sin(θ°) = √(2)/2
θ° = 360°n + sin⁻¹(√(2)/2) and θ° = 360°n + 180° −
sin⁻¹(√(2)/2)
θ° = 360°n + 45° and θ° = 360°n + 135° where n∈ℤ
360°*0 + 45° = 45°
360°*0 + 135° = 135°
360°*1 + 45° = 405°
<span>sin(225°) = -√(2)/2
</span>225 has an angle where sin theta= -(sqrt2)/2 therefore, the value of theta
cannot be 225 degrees.
Answer:
225° is not possible
Step-by-step explanation:
Given that

we have to choose the option which could not be the value of theta.



As sine is positive in second and fourth quadrant.
⇒ 
Also, 

Therefore 225° is not possible
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