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DochEvi [55]
2 years ago
5

Can someone help me with this math equation? Can you explain how to work it out also?

Mathematics
2 answers:
leonid [27]2 years ago
5 0

Answer: 50

<h2>Explanation:</h2><h3>What we know:</h3>
  • The numerator is 6
  • The denominator is equal to (3*5)^(-2)
  • In fraction-style equations, the numerators are divided by denominators
  • Negative exponents are equal to (base)^|power|, and then reversing the products place in the fraction

<h3>How to solve:</h3>

    By utilizing our knowledge of the PEMDAS solving method, negative powers, and fraction-style equations, this problem can be solved with a simple step-by-step procedure

<h2>Process:</h2><h3>Exponent</h3>

Set up equation                                                            6 / [3 * 5^(-2)]

Rewrite power                                                              6 / [3 * (5 * 5)]

Simplify power                                                              6 / [3 * (25)]

Invert power                                                                  6(25) / 3

<h3>Simplifying</h3>

Set up equation                                                            6(25) / 3

Simplify                                                                          150 / 3

Simplify (using common denominator)                        50 / 1

Rewrite in simplest form                                               =50

Answer: 50

lawyer [7]2 years ago
3 0
50 I did this one yesterday
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mrs_skeptik [129]

Answer:

\displaystyle a:b=\frac{1}{3}

Step-by-step explanation:

<u>Ratios </u>

We are given the following relations:

a=\sqrt{7}+\sqrt{c}\qquad \qquad[1]

b=\sqrt{63}+\sqrt{d}\qquad \qquad[2]

\displaystyle \frac{c}{d}=\frac{1}{9} \qquad \qquad [3]

From [3]:

9c=d

Replacing into [2]:

b=\sqrt{63}+\sqrt{9c}

We can express 63=9*7:

b=\sqrt{9*7}+\sqrt{9c}

Taking the square root of 9:

b=3\sqrt{7}+3\sqrt{c}

Factoring:

b=3(\sqrt{7}+\sqrt{c})

Find the ration a:b:

\displaystyle a:b=\frac{\sqrt{7}+\sqrt{c}}{3(\sqrt{7}+\sqrt{c})}

Simplifying:

\boxed{a:b=\frac{1}{3}}

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Step-by-step explanation:

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Can anyone help me ???
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Look at the following function <br> X -12 -8
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