Answer:
![y(x)=C_{1}cos2x+C_{2}sin(2x)](https://tex.z-dn.net/?f=y%28x%29%3DC_%7B1%7Dcos2x%2BC_%7B2%7Dsin%282x%29)
Step-by-step explanation:
It is a linear homogeneous differential equation with constant coefficients:
y" + 4y = 0
Its characteristic equation:
r^2+4=0
r1=2i
r2=-2i
We use these roots in order to find the general solution:
![y(x)=C_{1}cos2x+C_{2}sin(2x)](https://tex.z-dn.net/?f=y%28x%29%3DC_%7B1%7Dcos2x%2BC_%7B2%7Dsin%282x%29)
Answer:
if there are 360 students, the number of teacher will be 6,480...
360:6,480
Answer:
Answer:(15,65) (30,60)(45,55)
Step-by-step explanation:
Sorry for that kid that did not answer
For this use the law of sines:
![\sin( \alpha ) \div a = \sin( \beta ) \div b \\ \sin( \alpha ) \div 11 = \sin(103) \div 16](https://tex.z-dn.net/?f=%20%5Csin%28%20%5Calpha%20%29%20%5Cdiv%20a%20%3D%20%5Csin%28%20%5Cbeta%20%29%20%5Cdiv%20b%20%5C%5C%20%5Csin%28%20%5Calpha%20%29%20%5Cdiv%2011%20%3D%20%5Csin%28103%29%20%5Cdiv%2016)
![\frac{ \sin( \alpha ) }{11} = \frac{0.97}{16}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%5Csin%28%20%5Calpha%20%29%20%7D%7B11%7D%20%3D%20%5Cfrac%7B0.97%7D%7B16%7D%20)
cross-multiply:
16×sin (J) = 11×0.97
sin(J) = 10.72/16
sin(J) = 0.67
hit the "arcsin" button on your calculator:
![{ \sin}^{ - 1} (0.67) = 42.06 = 42.1 \: deg](https://tex.z-dn.net/?f=%7B%20%5Csin%7D%5E%7B%20-%201%7D%20%280.67%29%20%3D%2042.06%20%3D%2042.1%20%5C%3A%20deg)
therefore answer B. 42 is the correct answer!!