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ValentinkaMS [17]
3 years ago
5

A dollar bill is worth _____ pennies. When written in decimal format, each penny can be written as ______ of a dollar. 100:10 10

0:1 100:0.1 100:0.01\
Please actually answer it correctly.
Mathematics
2 answers:
erik [133]3 years ago
5 0
Hey there! :D

A dollar bill is worth 100 pennies. 

$1.00-> .01*100 <=== same thing

When written in decimal format, each penny can be written as 100:1, because there are 100 pennies in a dollar. One penny would just be one out of 100. 

I hope this helps!
~kaikers
bekas [8.4K]3 years ago
3 0
A dollar bill is equal to 100 pennies. Similarly, 100 pennies is equal to a dollar.

If we want to find the value of a penny in decimal form, we must set the following equation, using the left side to represent pennies and the right side to represent dollars (this equation cannot exist, but does anyway for the sake of this question):

100 = 1

We want to get the left side to equal 1, so we divide both sides by the value of the left side:

1 = \frac{1}{100}

Solve the fraction and turn it into a decimal:

1 \div 100 = 0.01

This would mean that a penny is worth 1%, or 0.01 of a dollar.

The ratio that would fit this question is 100:0.01.
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s=P-b/2

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P-b=2s

P-b/2=s

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6 0
3 years ago
Ben consumes an energy drink that contains caffeine. After consuming the energy drink, the amount of caffeine in Ben's body decr
Airida [17]

Answer:

The 5-hour decay factor for the number of mg of caffeine in Ben's body is of 0.1469.

Step-by-step explanation:

After consuming the energy drink, the amount of caffeine in Ben's body decreases exponentially.

This means that the amount of caffeine after t hours is given by:

A(t) = A(0)e^{-kt}

In which A(0) is the initial amount and k is the decay rate, as a decimal.

The 10-hour decay factor for the number of mg of caffeine in Ben's body is 0.2722.

1 - 0.2722 = 0.7278, thus, A(10) = 0.7278A(0). We use this to find k.

A(t) = A(0)e^{-kt}

0.7278A(0) = A(0)e^{-10k}

e^{-10k} = 0.7278

\ln{e^{-10k}} = \ln{0.7278}

-10k = \ln{0.7278}

k = -\frac{\ln{0.7278}}{10}

k = 0.03177289938&#10;

Then

A(t) = A(0)e^{-0.03177289938t}

What is the 5-hour growth/decay factor for the number of mg of caffeine in Ben's body?

We have to find find A(5), as a function of A(0). So

A(5) = A(0)e^{-0.03177289938*5}

A(5) = 0.8531

The decay factor is:

1 - 0.8531 = 0.1469

The 5-hour decay factor for the number of mg of caffeine in Ben's body is of 0.1469.

7 0
3 years ago
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