QUESTION 1
A survey of 85 randomly selected homeowners finds that they spend a mean of $67 per month on home maintenance with a standard
deviation of $14. Construct and interpret a 99% confidence interval for the mean amount of money spent per month on home
maintenance by all homeowners.
What is ?
If necessary, round your answer to three decimal places
QUESTION 2
0
A survey of 85 randomly selected homeowners finds that they spend a mean of S67 per month on home maintenance with a standard
deviation of $14. Construct and interpret a 99% confidence interval for the mean amount of money spent per month on home
maintenance by all homeowners.
What is the t-multiplier?
if necessary, round your answer to three decimal places.
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Answer:
1875
Step-by-step explanation:
After sharing in the ratio 5:3, the brother has
5000/(5+3) x 5 = 3125
Next, he shares with his friend in the ratio 3:1:1, thus
3125/(3+1+1) x 3 = 1875
I have linked a picture with the intervel.
-z³ + 5k^6 + z³ -10k^6
(-z³ cancels out with z³)
5k^6 -10k^6
(then subtract)
Answer is -5k^6
