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Yuri [45]
3 years ago
10

Given problem type SAA or ASA, how would you solve for the length of any of the remaining sides?

Mathematics
2 answers:
ASHA 777 [7]3 years ago
8 0
Use the fact that the angles add up to 180 degrees, and then use the law of sines.
VMariaS [17]3 years ago
3 0
This is the concept of geometry and trigonometry, when you have been givn a problem type SAA (side-angle-angle) or ASA (Angle-side-angle), to solve the problem of this kind we use the sine rule which states that given triangle ABC with sides a,b,c. Then;
a/sin A=b/sin B=c/sin C
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A sample of n = 4 scores is selected from a population with m = 40 with s = 8, and the sample mean is M = 43. What is the standa
vladimir2022 [97]
Standard error (SE)
se=   \frac{s}{ \sqrt{n} }
Or

se =  \sqrt{ \frac{ {s}^{2} }{n} }

Therefore, SE of the mean = (8)/(2) =4
5 0
3 years ago
Is 5 + 3x1 - x) equivalent to 8 – 8x?
nalin [4]

Answer:

no

Step-by-step explanation:

5+3x is equal to 8x.

if there is no number in front of a variable, it is understood to be a one. so 1-x would basically be 1-1. this cancels out the x, making it impossible for the equivalent equation to be 8 - 8x

3 0
3 years ago
PLEASE HELP IVE ASKED THIS QUESTION 3 TIMES PLEASE HELP!!!!!!!!!!!!!!!!!!!!!!!!​
worty [1.4K]

THEOREM:

  • h² = p² + b² where h is hypotenuse, b is base and p is perpendicular.

ANSWER:

[3] By pythagorean theorem,

  • x² = 14² + 9²
  • x² = 196 + 81
  • x² = 277
  • x = √277
  • x = 16.64 rounded.

[4] By pythagorean theorem,

  • x² = 32² + 24²
  • x² = 1024 + 576
  • x² = 1600
  • x = √1600
  • x = 40.

[5] By pythagorean theorem,

  • (2x)² = 21² – 12.6²
  • 4x² = 441 – 158.76
  • 4x² = 284.24
  • x² = 284.24/4 = 70.56
  • x = √70.56
  • x = 8.4

[6] By tangent property,

  • 7x – 29 = 2x + 16
  • 7x – 2x = 16 + 29
  • 5x = 45
  • x = 9.

So, WX = 7(9) – 29 = 63 – 29

  • WX = 34
4 0
3 years ago
Determine the equations of the vertical and horizontal asymptotes, if any, for y=x^3/(x-2)^4
djverab [1.8K]

Answer:

Option a)

Step-by-step explanation:

To get the vertical asymptotes of the function f(x) you must find the limit when x tends k of f(x). If this limit tends to infinity then x = k is a vertical asymptote of the function.

\lim_{x\to\\2}\frac{x^3}{(x-2)^4} \\\\\\lim_{x\to\\2}\frac{2^3}{(2-2)^4}\\\\\lim_{x\to\\2}\frac{2^3}{(0)^4} = \infty

Then. x = 2 it's a vertical asintota.

To obtain the horizontal asymptote of the function take the following limit:

\lim_{x \to \infty}\frac{x^3}{(x-2)^4}

if \lim_{x \to \infty}\frac{x^3}{(x-2)^4} = b then y = b is horizontal asymptote

Then:

\lim_{x \to \infty}\frac{x^3}{(x-2)^4} \\\\\\lim_{x \to \infty}\frac{1}{(\infty)} = 0

Therefore y = 0 is a horizontal asymptote of f(x).

Then the correct answer is the option a) x = 2, y = 0

3 0
3 years ago
Read 2 more answers
Can someone pls help me?
nignag [31]

Step-by-step explanation:

ofc , so that is that and the other is that

4 0
3 years ago
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