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tino4ka555 [31]
3 years ago
9

Jose borrows $200 for 2 years at a rate of 8% simple interest calculated annually. How much will he have to pay back at the end

of 2 years?
Mathematics
1 answer:
KatRina [158]3 years ago
6 0
Annually= per year

200 at 8% the first year would be
200 • 0.08 = 16 per year
2 years = 32 dollars in interest at the end of 2 years
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The length of the third side of the triangle is 30.

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Here is the formula for the Pythagorean Theorem:

a^{2} + b^{2} = c^{2}

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We need to multiply 40 times 40 and 50 times 50.

40 times 40, or 40 squared, equals to 1600.

50 times 50, or 50 squared, equals to 2500.

c^{2} - b^{2}  = a^{2}

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Answer:

P(A) = 0.45

P(B) = 0.32

Step-by-step explanation:

Given

P(A) > P(B)

P(A\ u\ B) = 0.626

P(A\ n\ B) = 0.144

Required

Find P(A) and P(B)

We have that:

P(A\ u\ B) = P(A) + P(B) - P(A\ n\ B) --- (1)

and

P(A\ n\ B) = P(A) * P(B) --- (2)

The equations become:

P(A\ u\ B) = P(A) + P(B) - P(A\ n\ B) --- (1)

0.626 = P(A) + P(B) - 0.144

Collect like terms

P(A) + P(B) = 0.626 + 0.144

P(A) + P(B) = 0.770

Make P(A) the subject

P(A) = 0.770 - P(B)

P(A\ n\ B) = P(A) * P(B) --- (2)

0.144 = P(A) * P(B)

P(A) * P(B) = 0.144

Substitute: P(A) = 0.770 - P(B)

[0.770 - P(B)] * P(B) = 0.144

Open bracket

0.770P(B) - P(B)^2 = 0.144

Represent P(B) with x

0.770x - x^2 = 0.144

Rewrite as:

x^2 - 0.770x + 0.144 = 0

Expand

x^2 - 0.45x - 0.32x + 0.144 = 0

Factorize:

x[x - 0.45] - 0.32[x - 0.45]= 0

Factor out x - 0.45

[x - 0.32][x - 0.45]= 0

Split

x - 0.32= 0 \ or\ x - 0.45= 0

Solve for x

x = 0.32\ or\ x = 0.45

Recall that:

P(B) = x

So, we have:

P(B) = 0.32 \ or \ P(B) = 0.45

Recall that:

P(A) = 0.770 - P(B)

So, we have:

P(A) = 0.770 - 0.32 \ or\ P(A) =0.770 - 0.45

P(A) = 0.45 \ or\ P(A) =0.32

Since:

P(A) > P(B)

Then:

P(A) = 0.45

P(B) = 0.32

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3 years ago
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