F(x) = 2(2)^x-1<span>f(5)=32</span>
It looks like you have a right-angled triangle with hypotenuse of 12 and a base of 10
<span>h^2 + 10^2 = 12^2 </span>
<span>h^2 + 100 = 144 </span>
<span>h^2 = 44 </span>
<span>h = √44 = appr 6.6</span>
Answer:
We have the function:
r = -3 + 4*cos(θ)
And we want to find the value of θ where we have the maximum value of r.
For this, we can see that the cosine function has a positive coeficient, so when the cosine function has a maximum, also does the value of r.
We know that the meaximum value of the cosine is 1, and it happens when:
θ = 2n*pi, for any integer value of n.
Then the answer is θ = 2n*pi, in this point we have:
r = -3 + 4*cos (2n*pi) = -3 + 4 = 1
The maximum value of r is 7
(while you may have a biger, in magnitude, value for r if you select the negative solutions for the cosine, you need to remember that the radius must be always a positive number)
<span> 1/5 +20.4-(-5 3/4
1/5 as a decimal is .2
3/4 as a decimal is .75
.2+20.4-(-5.75)
20.6-(-5.75)
</span>26.35 <<< would be your answer
Answer:
40.5 degrees
Step-by-step explanation:
A triangle's angles all add up to 180 degrees, so to solve this all you need to do is add the two numbers you have and subtract them from 180.
62.5+77+x=180
139.5+x=180
-139.5 -139.5
x=40.5