J, K, and L are collinear
J is between K and L
LK = KJ + LJ
LK = 9x + 7
KJ = 2x - 3
LJ = 4x - 8
9x + 7 = (2x - 3) + (4x - 8)
9x + 7 = (2x + 4x) + (-3 - 8)
9x + 7 = 6x + -11
9x + 7 = 6x - 11
9x + 7 - 7 = 6x - 11 - 7
9x = 6x - 18
9x - 6x = 6x - 6x - 18
3x = -18
x = -6
∴ The value of x is -6
Answer:A is a subset of D
Step-by-step explanation:
Because A has what it is contained D
Answer:
r = 0.0424 cm (3sf)
Step-by-step explanation:
it makes 150 rev/sec
1 revolution = 1 circumference = 2pi*r
so every second the spool goes through 2*pi*r*150 of distance
we know that the rate of pulling is 40cm/sec
so 2pi*r*150 = 40
r = 40/(2pi*150), which is 0.04244131816 cm.
check: Circumference is 2pi*r = 0.2666
now multiply by 150rev/sec = 40 cm/sec
Answer:
Then the total area is 116 cm^2 which agrees with answer D
Step-by-step explanation:
Notice we need to calculate the area of two rectangles (one larger at the bottom and a smaller one on top)
The Area of a rectangle is the product: base x height
In our case :
Area of Big rectangle = 12 cm x 7 cm = 84 cm^2
Area of smaller rectangle = 8 cm x 4 cm = 32 cm^2
Then the total area is: 84 cm^2 + 32 cm^2 = 116 cm^2
