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allochka39001 [22]
2 years ago
7

Points ), K and L are collinear with J between L and K. IF KJ = 28 - 3, LK = 9x + 7 and LJ = 4x - 8,

Mathematics
1 answer:
babymother [125]2 years ago
6 0

J, K, and L are collinear

J is between K and L

LK = KJ + LJ

LK = 9x + 7

KJ = 2x - 3

LJ = 4x - 8

9x + 7 = (2x - 3) + (4x - 8)

9x + 7 = (2x + 4x) + (-3 - 8)

9x + 7 = 6x + -11

9x + 7 = 6x - 11

9x + 7 - 7 = 6x - 11 - 7

9x = 6x - 18

9x - 6x = 6x - 6x - 18

3x = -18

x = -6

∴ The value of x is -6

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Homework Help! ASAP
Mariana [72]

Answer:

The cost of apple juice per ounce is 20 cents.

Explanation:

We know that a

16

ounce bottle is

$

3.20

and we want to find how much per ounce is.

So we set up a proportion and let

x

be the cost of one ounce:

16

3.20

=

1

x

Now we can cross multiply:

16

x

=

3.20

Divide both sides by

16

:

16

x

16

=

3.20

16

Therefore,

x

=

0.20

The cost of apple juice per ounce is 20 cents.

Hope this helps!

Step-by-step explanation:

3 0
3 years ago
WILL MARK BRAINLIEST <br><br> what is the domain of (f/g) (x)?
tatyana61 [14]

Given that f(x) = \sqrt{7-x} and g(x) = \sqrt{x + 2}, we can say the following:

\Bigg(\dfrac{f}{g}\Bigg)(x) = \dfrac{f (x)}{g(x)} = \dfrac{\sqrt{7 - x}}{\sqrt{x+2}}


Now, remember what happens if we have a negative square root: it becomes an imaginary number. We don't want this, so we want to make sure whatever is under a square root is greater than 0 (given we are talking about real numbers only).


Thus, let's set what is under both square roots to be greater than 0:

\sqrt{7 - x} \Rightarrow 7 - x \geq 0 \Rightarrow x \leq 7

\sqrt{x + 2} \Rightarrow x + 2 \geq 0 \Rightarrow x \geq -2


Since both of the square roots are in the same function, we want to take the union of the domains of the individual square roots to find the domain of the overall function.

x \leq 7 \,\,\cup x \geq -2 = \boxed{-2 \leq x \leq 7}


Now, let's look back at the function entirely, which is:

\Bigg( \dfrac{f}{g} \Bigg)(x) = \dfrac{\sqrt{7 - x}}{\sqrt{x+2}}

Since \sqrt{x + 2} is on the bottom of the fraction, we must say that \sqrt{x + 2} \neq 0, since the denominator can't equal 0. Thus, we must exclude \sqrt{x + 2} = 0 \Rightarrow x + 2 = 0 \Rightarrow x = -2 from the domain.


Thus, our answer is Choice C, or \boxed{ \{ x | -2 < x \leq 7 \}}.


<em>If you are wondering why the choices begin with the x | symbol, it is because this is a way of representing that x lies within a particular set.</em>

6 0
3 years ago
Alaine has 1 gallon of paint. She is going to pour it into a paint tray that measures 10 inches wide, 12 inches long, and 5 cm d
Serggg [28]
What is the question?
5 0
3 years ago
Which graph represents a line with a slope of and a y-intercept equal to that of the line y = x – 2?
Sindrei [870]

Answer:

(0, -2), (1, -1), (2,0)

Step-by-step explanation:

 should be along those lines

8 0
3 years ago
Can anyone pls help. If in you don't know pls don't answer it there is some people doing it to me pls don't I just need help wit
Dennis_Churaev [7]

Answer:

2500m2

Step-by-step explanation:

A square has four sides and the area is 10,000 m^2. Area is determined by multiplying two sides. In this case, you can divide by two to get 5000, then again by 2 to get 2500.  Each side/dimensions are 2500m^2

4 0
3 years ago
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