Question

2. A basket contains 6 apples, 5 bananas, 4 oranges and 5 peaches. If you randomly choose one piece of fruit, eat it and then choose another, what is the probability that you would choose a banana and then an apple? (Enter your answer as a whole number percent.)

Answer 1

Haven't done this since 7th grade (Last year)
The total would be 20 fruit
5    (for the Bananas) times 6 
20                                        20
=3/40
=.075
x100
=7.5% Chance

Answer 2

Answer:

8% as a whole number percent

Step-by-step explanation:

Number of;

Apples = 6

Bananas = 5

Oranges = 4

Peaches = 5

Total number of fruits in the basket = 6 + 5 + 4 + 5

= 20

Probability of picking a banana and then an apple

= (5/20) × (6/19)

= 30/380

= 3/38

=7.89% ≈ 8%