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3 years ago

Find the percent change from 2.15 to 1.99

Mathematics

1 answer:

MArishka [77]3 years ago

7 0

The answer is -7.44%
Formula: [(New Value – Old Value)/Old Value] x 100 = Answer

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Number 28 HELP!!!! I don't know

Leokris [45]

It is letter C.) can u tell

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2 years ago

What is the mode of 1 4 6 7 12 12 15

viktelen [127]

Answer:

The answer is 12

If you look at the set of data 12 is shown the most or there more then once when the others aren't

3 0

2 years ago

Dave walked to his friends house at a rate of 4 mph and returned biking at a rate of 10 mph. If it took him 18 minutes longer to

vesna_86 [32]

Answer:

The total distance of the round trip was 4 miles

Step-by-step explanation:

1. Let's check all the information given to answer the question correctly:

Speed of Dave walking to his friend's house = 4 mph

Speed of Dave biking from his friend's house = 10 mph

Time walking is 18 minutes longer than time biking

2. What was the total distance of the round trip?

Time walking = x

Time biking = x - 18

For solving x, we will use the following equation:

4x = 10 * (x - 18)

4x = 10x - 180

-6x = - 180

x = -180/-6 (Dividing by - 6)

x = 30

Dave walked 30 minutes and biked 12 minutes, now we can calculate the total distance, this way:

30 minutes = 0.5 hours and 12 minutes = 0.2 hours

Total distance = 4 *0.5 + 10 * 0.2

Total distance = 2 + 2

Total distance = 4 miles.

3 0

2 years ago

Read 2 more answers

PLS TRY TO ANSWER ASAP.

Harrizon [31]

Answer:

0.075 m/min

Explanation:

You need to use derivatives which is an advanced concept used in calculus.

1. Write the equation for the volume of the cone:

$V=\dfrac{1}{3}\pi r^2h$

2. Find the relation between the radius and the height:

r = diameter/2 = 5m/2 = 2.5m

h = 5.2m

h/r =5.2 / 2.5 = 2.08

3. Filling the tank:

Call y the height of water and x the horizontal distance from the axis of symmetry of the cone to the wall for the surface of water, when the cone is being filled.

The ratio x/y is the same r/h

x/y=r/h

y = x . h / r

The volume of water inside the cone is:

$V=\dfrac{1}{3}\pi x^2y$

$V=\dfrac{1}{3}\pi x^2(2.08)\cdot x\\\\\\V=\dfrac{2.08}{3}\pi x^3$

4. Find the derivative of the volume of water with respect to time:

$\dfrac{dV}{dt}=2.08\pi x^2\dfrac{dx}{dt}$

5. Find x² when the volume of water is 8π m³:

$V=\dfrac{2.08}{3}\pi x^3\\\\\\8\pi=\dfrac{2.08}{3}\pi x^3\\\\\\ 11.53846=x^3\\ \\ \\ x=2.25969\\ \\ \\ x^2=5.1062$ m²

6. Solve for dx/dt:

$1.2m^3/min=2.08\pi(5.1062m^2)\dfrac{dx}{dt}$

$\dfrac{dx}{dt}=0.03596m/min$

7. Find dh/dt:

From y/x = h/r = 2.08:

$y=2.08x\\\\\\\dfrac{dy}{dx}=2.08\dfrac{dx}{dt}\\\\\\\dfrac{dy}{dt}=2.08(0.035964m/min)=0.0748m/min\approx0.075m/min$

That is the rate at which the water level is rising when there is 8π m³ of water.

4 0

3 years ago

Solve (-36 4/9)- (-10 2/9)- (18 2/9)

Elodia [21]

49.33, should be right

4 0

3 years ago