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kifflom [539]
4 years ago
13

-1/2 -(-1/5 to the 2nd power)

Mathematics
1 answer:
Thepotemich [5.8K]4 years ago
6 0
The answer is -27/50
You might be interested in
(30 points)
sesenic [268]

Hi,

The equation: (3^6)^2 x (3^0)

Multiply:

=(729^2)(3^0)

=531441 (3^0)

Simplify:

=(531441) (1)

Multiply again:

=531441 or D. (3^12)

Have a great day!

7 0
3 years ago
Read 2 more answers
Find the <br> x<br> -intercept and <br> y<br> -intercept of the line.<br> 2x-3y=6
Mumz [18]
Y-intercept= (0,2)
x-intercept= (3,0)
Why?
The x-intercept is when y is 0 and y-intercept is when x is 0.
5 0
3 years ago
If 3b + 4 = 10, then 5b + 4 =
Sveta_85 [38]

Answer:

12

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
The table below shows the radius y, in inches, created by growing algae in x days:
Pie
Part A. The correlation coefficient, denotes as R^2, is a measure of how well does the data point correlate with a given model or equation. The closer the R^2 is to 1, the better is the correlation. However, R2=1 is ideal for scatter plots. Using the MS Excel to execute the regression, the data points was fitted to a quadratic equation. The R2=0.9983. From the choices, the closest answer would be 1. But as stated previously, a value of 1 is ideal only. Therefore, the answer is most likely 0.94,


Part B. To determine the slope, the equation would be Δy/Δx. For x=5 and x=10, the slope would be

Slope = (3-1)/(10-5) = 2/5 or 0.4. This is the instantaneous rate of change at the interval of 5 to 10 days.

Part C. The difference between causation and correlation is identifiable if you know the direct relationship between the variables. In this case, the increase in radius is not caused by time. The problem does not state so. But we know from the trend shown on a graph, that there is a correlation between these variables. Therefore, the answer is correlation.

5 0
3 years ago
In game 1 emerson struck out 30 times in 90 times at bat in game 2 he struck out 40 times in 120 times at bat
Agata [3.3K]

Answer:

a) 32

b) 67.613

Step-by-step explanation:

<em><u> In Game 3, Emerson struck out 42 times in 140 times at-bat.</u></em>

<em><u>Part A</u></em>

<em><u>Drag numbers to complete the proportion to represent the percent of strikeouts per at-bats.</u></em>

<em><u>Numbers may be used once or not at all.</u></em>

<em><u /></em>

<em><u>Part B</u></em>

<em><u>What percentage of times at bat did Emerson actually hit the ball?</u></em>

Part A

Total number of strikeouts= 30+40+42= 112

Total number of at bats = 90+120+140= 350

strikeouts : times

112: 350

p:100

Using cross product rule

p/100= 112/350

p * 350= 112*100

or p= 11200/350= 32

It means that there were 32 strikeouts if 100 times were bat at hits.

Part B:

Total number of strikeouts= 30+40+42= 112

Total number of at bats = 90+120+140= 350

But we need the percentage of times at bat hit

Therefore

Hits= times - strikeouts= 350-112= 238

Percentage = 238/352*100= 67.613

Check

The above answers are correct because

100-32 = 68

68 ≅ 67.613

7 0
3 years ago
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