I don't know how to find the answer and draw where
1 answer:
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We have to find midpoint M of the diagonal AC (or BD, there is no difference) so:
Given:
In a two-digit number, the tens digit is 5 less than the units digit.
The number itself is five more than three times the sum of its digits.
To find:
The number.
Solution:
Let the two digit number is ab. So,
Tens digit is 5 less than the units digit.
...(i)
The number itself is five more than three times the sum of its digits.
...(ii)
Using (i) and (ii), we get
Putting b=8 in (i), we get
Therefore, the required number is 38.