To solve the question we shall use the formula for the range given by:
Horizontal range, R=[v²sin 2θ]/g
plugging in our values we get:
500=[160²×sin 2θ]/10
5000=160²×sin 2θ
0.1953=sin 2θ
thus:
arcsin 0.1953=2θ
11.263=2θ
hence:
θ=5.6315°~5.63
Answer:
its up.
Step-by-step explanation:
PLZ, MARK ME BRAINIIEST!!
Answer:
Hira
Step-by-step explanation:
They are going at the fastest speed as 9 is the most
I think it’s QT EJ and HA