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3 years ago

How do I simplify this expression?

Mathematics

1 answer:

babymother [125]3 years ago

4 0

We can write

$3x^{3/2}-9x^{1/2}+6x^{-1/2}=3x^{2-1/2}-9x^{1-1/2}+6x^{-1/2}$

and see that each term has a common factor of $3x^{-1/2}$ ; factoring this from each term gives

$3x^{3/2}-9x^{1/2}+6x^{-1/2}=3x^{-1/2}(x^2-3x+2)$

We can factorize this further:

$3x^{-1/2}(x-2)(x-1)$

This is probably what is meant by "simplify"...

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Kim creates a model of a building. The scale of her model building is 1 foot to 8 inch. Some of the measurements are shown in th

Shalnov [3]

Answer:

Left

50 feet

Right

16 inches

10 inches

Step-by-step explanation:

Here, we want to make a conversion and fill in the empty spaces

The scale is 1 foot is 1/8 inch

To convert from foot to inch, we multiply by 1/8

To convert from inch to foot, we multiply by 8

Thus, we have ;

Let’s fill in the left spaces first;

6.25 * 8 = 50 feet

Right spaces, top to bottom;

128 * 1/8 = 16 inches

80 * 1/8 = 10 inches

7 0

3 years ago

You get paid \$14.50$14.50 an hour at your job and the newest video game costs \$85.00$85.00. Find the inequality that repr

Zielflug [23.3K]

Answer:

14.50x > 85

Step-by-step explanation:

14.50x > 85

divide both sides by 14.5

x>85/14.5 = 5.86 hours

x has to be greater than 5.86 hours

3 0

2 years ago

What are the coordinates of R' for the dilation D(0.5. p)(PQRS)?

11111nata11111 [884]

Answer:

$R' = (-1,-0.5)$

Step-by-step explanation:

See attachment for complete question.

From the attachment:

$P = (-3,-3)$

$R = (1,2)$

Dilation:

$D_{(0.5,P)}$

Required

Determine R'

First, subtract the coordinates of P from R. This means that R is measured from P.

$R = (1-(-3),2-(-3))$

$R = (1+3,2+3)$

$R = (4,5)$

Next, apply dilation factor 0.5

$R' = R * 0.5$

$R' = (4,5) * 0.5$

$R' = (4* 0.5,5* 0.5)$

$R' = (2,2.5)$

Lastly, measure R' from the origin by adding the coordinates of P to R'

$R' = (2+(-3),2.5+(-3))$

$R' = (2-3,2.5-3)$

$R' = (-1,-0.5)$

6 0

3 years ago

This is Matrix for pre calc

gavmur [86]

The given system of equations in augmented matrix form is

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\-6&1&2&4&-12\\1&-3&-3&5&-20\\-2&5&6&0&12\end{array}\right]$

If you need to solve this, first get the matrix in RREF:

Add 2(row 1) to row 2, row 1 to -3(row 3), and 2(row 1) to 3(row 4):

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&11&5&-13&37\\0&19&10&4&-10\end{array}\right]$

Add 11(row 2) to -5(row 3), and 19(row 1) to -5(row 4):

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&-164&132&-1052\end{array}\right]$

Add 164(row 3) to -91(row 4):

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&0&13080&-39240\end{array}\right]$

Multiply row 4 by 1/13080:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&0&1&-3\end{array}\right]$

Add -153(row 4) to row 3:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&0&-364\\0&0&0&1&-3\end{array}\right]$

Multiply row 3 by -1/91:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

Add 6(row 3) and -8(row 4) to row 2:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&0&0&-10\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

Multiply row 2 by 1/5:

$\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

Add -2(row 2), 4(row 3), and -2(row 4) to row 1:

$\left[\begin{array}{cccc|c}3&0&0&0&3\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

Multiply row 1 by 1/3:

$\left[\begin{array}{cccc|c}1&0&0&0&1\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]$

So the solution to this system is $(w,x,y,z)=(1,-2,4,-3)$ .

6 0

4 years ago

What percent of 260 is 78

Reptile [31]

If you are using a calculator, simply enter 78÷260×100 which will give you 30 as the answer.

4 0

3 years ago

Read 2 more answers