How do I simplify this expression?

Mathematics

1 answer:

babymother [125]2 years ago

4 0

We can write

$3x^{3/2}-9x^{1/2}+6x^{-1/2}=3x^{2-1/2}-9x^{1-1/2}+6x^{-1/2}$

and see that each term has a common factor of $3x^{-1/2}$ ; factoring this from each term gives

$3x^{3/2}-9x^{1/2}+6x^{-1/2}=3x^{-1/2}(x^2-3x+2)$

We can factorize this further:

$3x^{-1/2}(x-2)(x-1)$

This is probably what is meant by "simplify"...

You might be interested in

The quotient of (x^3+3x^2-4x-12)/(x^2+5x+6)

Elis [28]

Answer: The quotient is (x-2).

Step-by-step explanation:

Since we have given that

$f(x)=(x^3+3x^2-4x-12)\\\\and\\\\g(x)=x^2+5x+6\\\\So,\ \frac{\left(x^3+3x^2-4x-12\right)}{\left(x^2+5x+6\right)}$

Now, we have to find the quotient of the above expression.

So, here we go:

$Factorise\ (x^3+3x^2-4x-12)\\\\=\left(x^3+3x^2\right)+\left(-4x-12\right)\\\\=-4\left(x+3\right)+x^2\left(x+3\right)\\\\=\left(x+3\right)\left(x^2-4\right)$

Now, we will divide the above simplest form with g(x):

$\frac{\left(x+3\right)\left(x^2-4\right)}{\left(x+2\right)\left(x+3\right)}\\\\=\frac{x^2-4}{x+2}\\\\=\frac{\left(x+2\right)\left(x-2\right)}{x+2}\ using\ (a^2-b^2)=(a+b)(a-b)\\\\=x-2$