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SSSSS [86.1K]
3 years ago
5

What is the equation in standard form for (0,3) and (7,0)

Mathematics
1 answer:
Luden [163]3 years ago
3 0

Answer:

3x + 7y = 21

Step-by-step explanation:

We have value of two points (0,3) and (7,0)

First, let's find the slope of this line. The formula for slope is:

Change in y/Change in x or (y₂ - y₁)/(x₂-x₁)

Where x₁ = 0 x₂= 7 y₁ = 3 y₂ = 0

(y₂ - y₁)/(x₂-x₁)

= (0-3)/(7-0)

=-3/7

Now we can write the equation in point-slope form:

y-y₁ = m(x-x₁)

y - 3 = -3/7(x-0)

y-3=-3x/7

y=-3x/7 + 3

Now let's convert this to standard form, by making the y-intercept by itself:

Ax + By = C

y=-3x/7 + 3

Multiply through by 7

7(y) = 7(-3x/7) + 7(3)

7y = -3x + 21

3x + 7y = 21

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svet-max [94.6K]
4x²+4x-35=0
factor: (2x+7)(2x-5)=0
2x+7=0, or 2x-5=0
2x=-7 or 2x=5
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I don't see any rounding necessary in this case. 

when you factor ax²+bx+c, you take the two factors of a and the two factors of c, one factor of a times one factor of c, the other factor of a times the other factors, the sum of the two products make b.
in this case, the factors of 4 is 2 and 2, the factors of -35 is -5 and 7. I line them up in the following way:
2    -5

2      7
then I multiple them diagonally, the top left 2 multiplying the bottom right 7=14, and the other 2 multiplying -5=-10, 14 and -10 make a sum of 4.

if you don't get the desired sum, switch the factors up and down till you have the right combination. Note: Do not switch left and right. 

I hope this makes sense to you.
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