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Archy [21]
4 years ago
13

Consider an AC circuit consisting of a power supply and a resistor. If the current in the circuit at time t is /, then the power

delivered to the resistor is /, where R is the resistance. Express the power in terms of cos 2wt
Mathematics
1 answer:
fenix001 [56]4 years ago
8 0

Answer:

P ( t ) = Io^2*R*0.5* (1 - cos ( 2wt) )

Step-by-step explanation:

Given:-

- The given current at time t, with maximum current supplied (Io) is:

                                 I(t) = Io*sin(tw)

Find:-

The power P in terms of cos (2wt)

Solution:-

- The formula for power (P) in an AC circuit is given by the expression:

                               P ( t ) = [I(t)]^2*R

                               P ( t ) = [Io*sin(tw)]^2 *R

                               P ( t ) = Io^2*R*sin(tw)^2

- We will use cos (2w) : Double angle formula as follows,

                              [sin(wt)]^2 = 0.5* (1 - cos ( 2wt) )

- Substituting in our power expression we have:

                             P ( t ) = Io^2*R*0.5* (1 - cos ( 2wt) )

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H_{0} = 45\\H_{1} < 45\\\\

The test statistic :

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T = -1.1155

At α = 0.05

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8 0
3 years ago
The equation of a circle is
sergij07 [2.7K]

Answer:

The answer is

<h3>center = ( - 7 , - 1)</h3><h3>radius = 6</h3>

Step-by-step explanation:

The general equation of a circle is given by

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where the center of the center of the circle is given by

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From the question the equation is

x² + y² + 14x + 2y + 14 = 0

Comparing with the general equation above we have

2g = 14 2f = 2

g = 7 f = 1 c = 14

So the center of the circle is

<h3>( - 7 , - 1)</h3>

The radius of a circle is given by

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Substitute the values into the above formula

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r =  \sqrt{ {7}^{2}  +  {1}^{2} - 14 }  \\ r =  \sqrt{49 + 1 - 14}  \\ r =  \sqrt{36}

we have the final answer as

<h3>radius = 6</h3>

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