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3 years ago

Use the table below to answer this question:

1 answer:

3 0

(y_final-y_start)/(x_final-x_start) always! :) that easy

(-6-2)/(2-0) = -4

You probably know that if the interval was pretty small, between 0 and 0.0001, it would take you to the concept of slope and derivatives, but average change is just ignoring anything in between x=0, and x=2 (it could go up/down million times, and still the answer would be -4)

hope it helps

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amir lent Rs. 600 to hameed for 2 years and Rs. 150 to aman for 4 year and received altogether from both Rs. 90 as simple intere

aniked [119]

Interest = Pin = principal * interest rate * number of years

Let interest rate be i, then
600*i*2+150*i*4=90
1200i+600i = 90
i=90/(1200+600)=90/1800=1/20=0.05 or 5%

8 0

3 years ago

The perimeter of a square is given as 8x+20. Write two different expressions for the perimeter. Use factoring to write one of th

sveticcg [70]

Answer:

P = 4(2x + 5)

P = (2x + 5)+(2x + 5)+(2x + 5)+(2x + 5)

Step-by-step explanation:

Given that:

Perimeter of square = 4 * s

Where s = side length

If perimeter, P = 8x + 20

Then,

4s = 8x + 20

Divide both sides by 4

4s / 4 = (8x + 20) / 4

s = 2x + 5

P = 4s

P = 4(2x + 5)

P = 2x + 5 in 4 places

P = (2x + 5)+(2x + 5)+(2x + 5)+(2x + 5)

8 0

3 years ago

48 divided by 76.8<br> I am very confused on the two digits numbers

Anestetic [448]

It’s 1.600 because it’a not the same when you round and it has different type of decimal places.

5 0

2 years ago

What is the slope of the line that is perpendicular to the line that passes through (-2, 7) and (4, 9)? Type a numerical answer

kodGreya [7K]

Answer:

Therefore $m_{2}$ = -3.

Step-by-step explanation:

i) let us say the slope of the line passing through (-2,7) and (4,9) is $m_{1}$ .

ii) to find the slope of the line passing through two points ( $x_{1}$ , $y_{1}$ ) and ( $x_{2}$ , $y_{2}$ ) we use the formula m = $\dfrac{y_{2} - y_{1} }{x_{2} - x_{1} }$ . Therefore we can say that $m_{1}$ = $\dfrac{9 - 7}{4 - (-2)}$ = $\dfrac{1}{3}$ .

iii) let us say the slope of the perpendicular line to the line passing through (-2,7) and (4,9) is $m_{2}$

iv) from the formula for the slopes of a line and the line perpendicular to it which is given by $m_{1}$ × $m_{2}$ = -1, therefore $m_{2}$ = -1 ÷ $m_{1}$ = -3. Therefore $m_{2}$ = -3

6 0

3 years ago

Solve the system of equations given below

Fantom [35]

$y-15=3x \\-2x+5y=-3 \\ \\-2x+y-15=0 /\cdot2 \\-2x+5y-3=0 /\cdot(-2) \\ \\-4x+2y-30=0 \\4x-10y+6=0 \\ \\-8y-24=0 \\\boxed{y=-3} \\ \\-3-15=3x \\\boxed{x=-6}$

The answer is C. (-6, -3)

Hope this helps.

r3t40

8 0

3 years ago

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