Plz help I'll give brainlest!!

Belief in UFOs A survey found that of people believe that they have seen a UFO. Choose a sample of people at random. Find the pr

Mkey [24]

Answer:

b is the answer am not sure you know

8 0

3 years ago

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What area of the clock is not covered with clock face in square inches

Kay [80]

Hello again,
We know that the clock has rectangular shapes, and the clock face is circle.
Area of the clock is:
15×8=120 square inches
To find the area of the circle:
πr^2. However, we did not know the radius yet, but we had circumference of the circle which is 6 inches
C=2πr
6=2πr
Divided 2 from both side
3=πr
Divide π or 3.14 from both side
r≈1 inches
Area of the clock face is:
1×1×3.14
≈3.14.
To find the area of the clock that does not covered with clock face take:
120-3.14=116.86 square inches. Hope it help!

8 0

3 years ago

Enter the number that belongs in the green box.

coldgirl [10]

Answer:

Angle D equals 80 degrees.

Since both triangles and angles are congruent, you can use triangle ABC to find the measure of CDE.

ABC has to equal 180 degrees so that means that 30 + 70 + <B = 180

add: 100 + <B = 180

Subtract <B = 80

Angle B equals 80 degrees which also means that Angle D equals 80 degrees.

6 0

3 years ago

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how many circles can be drawn passing through three non collinear points and how many circles can be drawn passing through three

MrRissso [65]

Answer:

Only one circle can be drawn through three non nonlinear points, No circle can be drawn through three nonlinear points

Step-by-step explanation:

A circle has a curve. As long as the three non nonlinear points both have the same amount of distance from the center of the circle it can be a circle drawn. No circle can be drawn through three points on the line.

7 0

3 years ago

I need help with problem 1 with a through explanation and solution please <br><br>

ki77a [65]

Explanation:

The cubic ...

f(x) = ax³ +bx² +cx +d

has derivatives ...

f'(x) = 3ax² +2bx +c

f''(x) = 6ax +2b

By definition, there will be a point of inflection where the second derivative is zero (changes sign). The second derivative is a linear equation in x, so can only have one zero. Since it is given that a≠0, we are assured that the line described by f''(x) will cross the x-axis at ...

f''(x) = 0 = 6ax +2b ⇒ x = -b/(3a)

The single point of inflection is at x = -b/(3a).

__

The cubic will have a local extreme where the first derivative is zero and the second derivative is not zero. These will only occur when the discriminant of the first derivative quadratic is positive. Their location can be found by applying the quadratic formula to the first derivative.

$x=\dfrac{-2b\pm\sqrt{(2b)^2-4(3a)(c)}}{2(3a)} = \dfrac{-2b\pm\sqrt{4b^2-12ac}}{6a}\\\\x=\dfrac{-b\pm\sqrt{b^2-3ac}}{3a}\qquad\text{extreme point locations when $b^2>3ac$}$

There will be zero or two local extremes. A local extreme cannot occur at the point of inflection, which is where the formula would tell you it is when there is only one.

__

Part A tells you the point of inflection is at x= -b/(3a).

Part B tells you the midpoint of the local extremes is x = -b/(3a). (This is half the sum of the x-values of the extreme points.) You will notice these are the same point.

The extreme points are located symmetrically about their midpoint, so are located symmetrically about the point of inflection.

_____

Additional comment

There are other interesting features of cubics with two local extremes. The points where the horizontal tangents meet the graph, together with the point of inflection, have equally-spaced x-coordinates. The point of inflection is the midpoint, both horizontally and vertically, between the local extreme points.

6 0

3 years ago