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Inessa05 [86]
3 years ago
9

What is the vertex if the function f(x)=-x^2-2x-1

Mathematics
1 answer:
Mila [183]3 years ago
7 0

Vertex=(-1,0)

x^2-2x-1

y=− ( x + 1 )^2 + 0

Use the vertex form, y=a(x−h)^2+k, to determine the values of a, h, and k.

Find the vertex (h,k) = (-1,0)

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<h3>Answer: Choice D</h3>

(f \circ g)(x) = x+12

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==================================================

Work Shown:

f(x) = x^2 + 9\\\\f(g(x)) = (g(x))^2 + 9\\\\f(g(x)) = (\sqrt{x+3})^2 + 9\\\\f(g(x)) = x+3 + 9\\\\f(g(x)) = x+12\\\\(f \circ g)(x) = x+12\\\\

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In step 3, we plugged in g(x) = sqrt(x+3)

The domain of g(x) is [-3, infinity), so this is the domain of (f \circ g)(x) as well since the composite function depends entirely on g(x). Put another way: the input of f(x) depends on the output of g(x), so that's why the domains match up.

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