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Inessa05 [86]
3 years ago
9

What is the vertex if the function f(x)=-x^2-2x-1

Mathematics
1 answer:
Mila [183]3 years ago
7 0

Vertex=(-1,0)

x^2-2x-1

y=− ( x + 1 )^2 + 0

Use the vertex form, y=a(x−h)^2+k, to determine the values of a, h, and k.

Find the vertex (h,k) = (-1,0)

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Can you help with #21 please. I will mark Brainliest.​
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Answer:

A, C, E

Step-by-step explanation:

By analyzing the graph, we can see that the roots are -2 and -4.

We now want to find all equations of the form (x-(-2))(x-(-4))=(x+2)(x+4)=0.

This immediately gives C as 1 answer.

We can expand our equation to find other possible solutions!

By the FOIL method: (x+2)(x+4)=(x)(x)+(2)(x)+(4)(x)+(2)(4)=x^2+6x+8=0

We can then divide both sides of the equation to find that -x^2-6x-8=0, so A is another answer.

We can complete the square on x^2+6x+8 to find the last possible solution.

x^2+6x+8=x^2+6x+9-9+8=x^2+6x+9-1=(x+3)^2-1=0.

We can then multiply both sides of the equation by 4 to find that 4(x+3)^2-4=0, so E is the last answer.

The proof that the other answers don't work is left as an exercise.

So, the answers are A, C, and E, and we're done!

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Solve 3.8 = p/3 - 7.2.<br><br> p =
laila [671]

Answer:

The answer is p=33.

Step-by-step explanation:

First you need to add 7.2 to the both sides in order to get rid of 7.2. On the left hand side, you'll have 11.0, directly 11. Since, \frac{p}{3} =11 multiply the both sides with 3, and you'll get p=33.

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Use PEMDAS

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E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

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and |a| = a for a ≥ 0 or |a| = -a for a < 0.

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