All categories

3 years ago

Estimate 19.164 - 9.53 by first rounding each number to the nearest tenth.

Mathematics

2 answers:

Delvig [45]3 years ago

6 0

Rounded to the nearest tenth:
19.164 would become 19.2
9.53 would become 9.5

19.2- 9.5= 9.7

Final answer: 9.7~

Lina20 [59]3 years ago

3 0

19.164 can be rounded to 19.2. That is because 0.164 is closer to 0.2 than it is to 0.1

9.53 rounded the the nearest tenth is 9.5 because 0.53 is closer to 0.5 than it is to 0.6.

19.2 - 9.5 = 9.7

Your answer is 9.7

You might be interested in

On a graph which line is horizontal and vertical? y or x

Dvinal [7]

Answer:

The Y is the vertical line and X is the horizontal line on the graph. So if you have point so (5,4). Five would be on the X-axis and 4 on Y-axis.

Step-by-step explanation:

4 0

3 years ago

Please help (PLEASE DO NOYPE GIBBERISH FOR POINTS.)

krok68 [10]

It was reduced because as you can see on the scale the actual picture has larger spaces between the numbers.

7 0

3 years ago

I rlly suck at math so plz help lol

Jlenok [28]

Answer:

A. 81

Step-by-step explanation:

Combine fractions, that equals 2/5 in your exponent. Three to the 2/5 power is 81. So answer A.

6 0

3 years ago

Read 2 more answers

Name/ Uid:1. In this problem, try to write the equations of the given surface in the specified coordinates.(a) Write an equation

Gemiola [76]

To find:

(a) Equation for the sphere of radius 5 centered at the origin in cylindrical coordinates

(b) Equation for a cylinder of radius 1 centered at the origin and running parallel to the z-axis in spherical coordinates

Solution:

(a) The equation of a sphere with center at (a, b, c) & having a radius 'p' is given in cartesian coordinates as:

$(x-a)^{2}+(y-b)^{2}+(z-c)^{2}=p^{2}$

Here, it is given that the center of the sphere is at origin, i.e., at (0,0,0) & radius of the sphere is 5. That is, here we have,

$a=b=c=0,p=5$

That is, the equation of the sphere in cartesian coordinates is,

$(x-0)^{2}+(y-0)^{2}+(z-0)^{2}=5^{2}$

$\Rightarrow x^{2}+y^{2}+z^{2}=25$

Now, the cylindrical coordinate system is represented by $(r, \theta,z)$

The relation between cartesian and cylindrical coordinates is given by,

$x=rcos\theta,y=rsin\theta,z=z$

$r^{2}=x^{2}+y^{2},tan\theta=\frac{y}{x},z=z$

Thus, the obtained equation of the sphere in cartesian coordinates can be rewritten in cylindrical coordinates as,

$r^{2}+z^{2}=25$

This is the required equation of the given sphere in cylindrical coordinates.

(b) A cylinder is defined by the circle that gives the top and bottom faces or alternatively, the cross section, & it's axis. A cylinder running parallel to the z-axis has an axis that is parallel to the z-axis. The equation of such a cylinder is given by the equation of the circle of cross-section with the assumption that a point in 3 dimension lying on the cylinder has 'x' & 'y' values satisfying the equation of the circle & that 'z' can be any value.

That is, in cartesian coordinates, the equation of a cylinder running parallel to the z-axis having radius 'p' with center at (a, b) is given by,

$(x-a)^{2}+(y-b)^{2}=p^{2}$

Here, it is given that the center is at origin & radius is 1. That is, here, we have, $a=b=0,p=1$ . Then the equation of the cylinder in cartesian coordinates is,

$x^{2}+y^{2}=1$

Now, the spherical coordinate system is represented by $(\rho,\theta,\phi)$

The relation between cartesian and spherical coordinates is given by,

$x=\rho sin\phi cos\theta,y=\rho sin\phi sin\theta, z= \rho cos\phi$

Thus, the equation of the cylinder can be rewritten in spherical coordinates as,

$(\rho sin\phi cos\theta)^{2}+(\rho sin\phi sin\theta)^{2}=1$

$\Rightarrow \rho^{2} sin^{2}\phi cos^{2}\theta+\rho^{2} sin^{2}\phi sin^{2}\theta=1$

$\Rightarrow \rho^{2} sin^{2}\phi (cos^{2}\theta+sin^{2}\theta)=1$

$\Rightarrow \rho^{2} sin^{2}\phi=1$ (As $sin^{2}\theta+cos^{2}\theta=1$ )

Note that $\rho$ represents the distance of a point from the origin, which is always positive. $\phi$ represents the angle made by the line segment joining the point with z-axis. The range of $\phi$ is given as $0\leq \phi\leq \pi$ . We know that in this range the sine function is positive. Thus, we can say that $sin\phi$ is always positive.

Thus, we can square root both sides and only consider the positive root as,

$\Rightarrow \rho sin\phi=1$

This is the required equation of the cylinder in spherical coordinates.

Final answer:

(a) The equation of the given sphere in cylindrical coordinates is $r^{2}+z^{2}=25$

(b) The equation of the given cylinder in spherical coordinates is $\rho sin\phi=1$

7 0

3 years ago

Rory was with some friends outside an ice cream parlor. He noticed that one out of every four people bought a vanilla cone. He w

mrs_skeptik [129]

C. would be the correct device to use in trials.

But the actual probability is:

(1-1/4)^5

243/1024

(about 23.73% chance none of the five chose vanilla)

7 0

3 years ago

Read 2 more answers