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3 years ago

Estimate 19.164 - 9.53 by first rounding each number to the nearest tenth.

Mathematics

2 answers:

Delvig [45]3 years ago

6 0

Rounded to the nearest tenth:
19.164 would become 19.2
9.53 would become 9.5

19.2- 9.5= 9.7

Final answer: 9.7~

Lina20 [59]3 years ago

3 0

19.164 can be rounded to 19.2. That is because 0.164 is closer to 0.2 than it is to 0.1

9.53 rounded the the nearest tenth is 9.5 because 0.53 is closer to 0.5 than it is to 0.6.

19.2 - 9.5 = 9.7

Your answer is 9.7

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Use the geometric mean (leg) theorem. what is the value of a?

dedylja [7]

$\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}$

Actually Welcome to the concept of Geometric Mean (leg) theorem.

So according to the rule, we know that, here altitude = h and left side is 6 and right side is 14 , so we get as,

==> altitude/left = right/altitude

==> h/6 = 14/h

==> h^2 = 14*6

==> h^2 = 84

2.) so now we apply the Pythagoras theorem in triangle ∆DCB

so we get as,

==> (14)^2 + h^2 = a^2

==> 196 + 84 = a^2

==> 280 = a^2

==> a = √280

==> after simplified => a = √70*4

==> a = 2√70 units

hence the correct answer is a => 2√70 units.

4 0

3 years ago

How do I find angle N?

vladimir2022 [97]

Answer:N is 22.5 I think

Step-by-step explanation:

Half of 90 is 45 and N looks like half of P and half of 45 is 22.5

3 0

3 years ago

Find the value of the variable y, for which:

schepotkina [342]

The value of the variable y is $y=6$

Explanation:

The given equation is $\frac{6}{y-4}-\frac{y}{y+2}=\left(\frac{6}{y-4}\right)\left(\frac{y}{y+2}\right)$

Taking LCM on LHS of the equation, we get,

$\frac{6(y+2)-y(y-4)}{(y-4)(y+2)}=\left(\frac{6}{y-4}\right)\left(\frac{y}{y+2}\right)$

Simplifying the term on RHS of the equation, we get,

$\frac{6(y+2)-y(y-4)}{(y-4)(y+2)}=\frac{6 y}{(y-4)(y+2)}$

Since, both the sides of the equation have the same denominator, we can cancel them.

Thus, we have,

$6(y+2)-y(y-4)=6 y$

Multiplying the terms within the bracket, we get,

$6y+12-y^2-4y=6 y$

Adding the like terms, we have,

$2y+12-y^2=6 y$

Subtracting both sides by $6 y$ , we have,

$-4y+12-y^2=0$

Factoring the equation, we get,

$(y+2)(y-6)=0$

$y=-2, y=6$

The values of the variable y are $y=-2, y=6$

At the point $y=-2$ , the equation $\frac{6}{y-4}-\frac{y}{y+2}=\left(\frac{6}{y-4}\right)\left(\frac{y}{y+2}\right)$ becomes undefined.

Thus, the value of the variable y is $y=6$

8 0

4 years ago

Rent-a-Bike supplies bikes to groups of people to cycle the countryside. They charge a daily rate of $150 for bikes for 20 peopl

7nadin3 [17]

Let y = daily rate

let x = number of people

let m = charge per person

let b = arbitrary cost

so, y=mx+b

150 = 20m + b

330 = 50m + b

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m = 6

b = 30

so linear relationship : y = 6x+30

if x = 30

y = 180 + 30

y = 210

8 0

3 years ago

Read 2 more answers

Given vectors<br> p=2i-j<br> q= -i+j<br> find 1. p+q, 2. p-q, 3. 2p-3q

Romashka [77]

Answer:

See below

Step-by-step explanation:

$p=2i-j$