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3 years ago

Based on data in the two way table which statement is true

Mathematics

2 answers:

Korolek [52]3 years ago

6 0

Can you please add the statement? Then I may be able to help you... Thanks!

FrozenT [24]3 years ago

4 0

Fam where is the table and asnwers

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Me. Hamm’s salary has increased by 25% over the last 10 years. If his original salary was 28000 per year , what is his current s

mr Goodwill [35]

28,000 x 25% = 7,000

28,000 + 7,000 = 35,000

5 0

3 years ago

Read 2 more answers

35 = 1/2(x-5)(x-14) what does x equal?

Yanka [14]

The answer is x=19.
Hope it helps! (:

3 0

3 years ago

A construction worker fills a mold with concrete. This solid figure represents the mold.

nadezda [96]

Answer:

volume = 338 x 20 = 6760 cm^3

Step-by-step explanation:

large rectangular top area = 14 x 22 = 308 cm^2

small rectangular top area = 6x5 = 30 cm^2

total top area = 308 + 30 = 338 cm^2

volume = 338 x 20 = 6760 cm^3

4 0

3 years ago

If the sum of the zereos of the quadratic polynomial is 3x^2-(3k-2)x-(k-6) is equal to the product of the zereos, then find k?

lys-0071 [83]

Answer:

Step-by-step explanation:

So I'm going to use vieta's formula.

Let u and v the zeros of the given quadratic in ax^2+bx+c form.

By vieta's formula:

1) u+v=-b/a

2) uv=c/a

We are also given not by the formula but by this problem:

3) u+v=uv

If we plug 1) and 2) into 3) we get:

-b/a=c/a

Multiply both sides by a:

-b=c

Here we have:

a=3

b=-(3k-2)

c=-(k-6)

So we are solving

-b=c for k:

3k-2=-(k-6)

Distribute:

3k-2=-k+6

Add k on both sides:

4k-2=6

Add 2 on both side:

4k=8

Divide both sides by 4:

k=2

Let's check:

$3x^2-(3k-2)x-(k-6) \text{ with }k=2$ :

$3x^2-(3\cdot 2-2)x-(2-6)$

$3x^2-4x+4$

I'm going to solve $3x^2-4x+4=0$ for x using the quadratic formula:

$\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\frac{4\pm \sqrt{(-4)^2-4(3)(4)}}{2(3)}$

$\frac{4\pm \sqrt{16-16(3)}}{6}$

$\frac{4\pm \sqrt{16}\sqrt{1-(3)}}{6}$

$\frac{4\pm 4\sqrt{-2}}{6}$

$\frac{2\pm 2\sqrt{-2}}{3}$

$\frac{2\pm 2i\sqrt{2}}{3}$

Let's see if uv=u+v holds.

$uv=\frac{2+2i\sqrt{2}}{3} \cdot \frac{2-2i\sqrt{2}}{3}$

Keep in mind you are multiplying conjugates:

$uv=\frac{1}{9}(4-4i^2(2))$

$uv=\frac{1}{9}(4+4(2))$

$uv=\frac{12}{9}=\frac{4}{3}$

Let's see what u+v is now:

$u+v=\frac{2+2i\sqrt{2}}{3}+\frac{2-2i\sqrt{2}}{3}$

$u+v=\frac{2}{3}+\frac{2}{3}=\frac{4}{3}$

We have confirmed uv=u+v for k=2.

4 0

2 years ago

5/8x - 11/2 = 3/4 <br> what does the x equal ?

Verizon [17]

Answer:

x=10

Step-by-step explanation:

5/8x - 11/2 = 3/4

Multiply each side by 8 to clear the fractions

8(5/8x - 11/2 = 3/4)

5x - 44 = 6

Add 44 to each side

5x-44+4= 6+4

5x= 50

Divide by 5

5x/5 = 50/5

x =10

6 0

2 years ago