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Sidana [21]
3 years ago
15

Does anyone know the answer

Mathematics
1 answer:
Nata [24]3 years ago
3 0
The answer will be “self interest”.
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1.Points A and B are to be mapped onto a number line according to two equations. The solution to the equation is the coordinate
ohaa [14]
.Kim is x years old. Jordan is 7 years older than Kim. Four times Jordan’s age is equal to 200. (a)Write an equation that could be used to solve for Kim’s age, x. (b)How old is Kim? (c)How old is Jordan? Answer:

Kim = x
Jordan = x + 7

4(x+7) = 200
4x + 28 = 200
4x = 200 - 28
4x = 172
x = 172/4
x = 43. Kim's age

Jordan: x + 7 → 43+7 = 50
5 0
3 years ago
Read 2 more answers
How to solve (5-x)^1/2-2x=0
Gnesinka [82]

Answer:

x=1

Step-by-step explanation:

hope this helped

7 0
2 years ago
A person died leaving behind inheritance of Rs. 300000. Distribute the amount among 4 sons and 3 daughters so that each son gets
yan [13]
S=2d

4s+3d=300000-80000

4s+3d=220000, now using s=2d in this equation you get:

4(2d)+3d=220000

8d+3d=220000

11d=220000

d=20000

So each daughter gets 20000 and each son gets 40000.
3 0
3 years ago
Question: The slope of the graph of the equation Y=2x-2 is 2. What is the y-intercept <br>​
11Alexandr11 [23.1K]

Answer:

final answer is simply -2

Step-by-step explanation:

The graph crosses the y axis at -2 on the vertical number line. The y intercept as an ordered pair is (0,-2). The x coordinate is always 0 for the y intercept.

4 0
3 years ago
Multiply the following rational expressions and simplify the result
GarryVolchara [31]

Answer:

Step-by-step explanation:

We have to solve the given expression,

\frac{9y-33y^2-3y^4}{100-49y^2}.\frac{7y^2+17y+10}{14y^2+28y}

\frac{9y-33y^2-3y^4}{100-49y^2}.\frac{7y^2+17y+10}{14y^2+28y} = \frac{-y(-9+33y+3y^3)}{100-49y^2}.\frac{7y^2+17y+10}{14y(y+2)}

                                   = \frac{-y(-9+33y+3y^3)}{(10-7y)(10+7y)}.\frac{7y^2+10y+7y+10}{14y(y+2)}

                                   = \frac{-y(-9+33y+3y^3)}{(10-7y)(10+7y)}.\frac{y(7y+10)+1(7y+10)}{14y(y+2)}

                                   = \frac{-y(-9+33y+3y^3)}{(10-7y)(10+7y)}.\frac{(y+1)(7y+10)}{14y(y+2)}

                                   = \frac{-3y(-3+11y+y^3)}{(10-7y)}.\frac{(y+1)}{14y(y+2)}

                                   = \frac{-3(-3+11y+y^3)}{(10-7y)}.\frac{(y+1)}{14(y+2)}

                                   = \frac{3(3-11y-y^3)(y+1)}{(10-7y)(14(y+2)}

3 0
3 years ago
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