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wel
3 years ago
5

What is the area of a rectangle with a length of 27 and a height of 56?

Mathematics
2 answers:
yaroslaw [1]3 years ago
7 0

Answer: 1,512 units^2

Step-by-step explanation: To find the area of a rectangle, multiply the length by the width. 27 x 56 =1512. Since you are finding the area, the answer would be squared.

LUCKY_DIMON [66]3 years ago
3 0

Answer:

A=1512

Step-by-step explanation:

The area of a rectangle with a length of 27 and a height of 56 is 1512.

Formula: A=wl

A=wl=56·27=1512

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dmitriy555 [2]
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1) multiply the 4 and the one in front of the x on the second term = 4 then

2) multiply x^2 times x^2 to get x^4, not x^3, so you can immediately eliminate A and B to save time.

Now let's deal with the second part..."may or may not be" part

A polynomial is an expression with more than two algebraic terms

terms are like...
2x + 3y ---there's two terms there, eventhough the 2 and x are multiplied, it doesn't count (same with the 3 and y)
since it only have two terms, not more than two terms, it is called a binomial, not polynomial. I think that's what they mean by that

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3 0
3 years ago
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Transversal cuts parallel lines and at points X and Y respectively. The point nearest to C is X, and the point nearest to D is Y
hammer [34]

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We are given four angles, out of which one should be chosen which is congruent to ∠CXP.

The angles lying on opposite sides of the transversal and outside the two parallel lines are called alternate exterior angles.

For example, in the figure attached, ∠CXP, ∠SYD and ∠CXQ, ∠RYD are pairs of alternate exterior angles.

Now, the theorem of alternate exterior angles states that if the two lines are parallel having a transversal, then alternate exterior angles are congruent to each other.

Thus, we have

∠CXP ≅ ∠SYD.

So, option (B) is correct.

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cestrela7 [59]
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Mekhanik [1.2K]
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GarryVolchara [31]

Answer:

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