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kipiarov [429]
4 years ago
15

How do I solve 4(5(6)) This is a hypothetical question

Mathematics
2 answers:
SSSSS [86.1K]4 years ago
6 0
PEMDAS states that the value in the parenthesis should be evaluated first:
4(5*6)
4(30)
After just multiply the value in the parenthesis by the number outside of the parenthesis:
120
Flura [38]4 years ago
4 0
Im not to sure but would it be 120?

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(3 3/4)÷(−2 1/2) plz help me
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Answer:

= -3/2

Step-by-step explanation:

3 3/4 = 15/4

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(15/4)/(-5/2)

= -3/2

ALTERNATIVE ANSWERS:

-1 1/2 or -1.5

8 0
3 years ago
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Licemer1 [7]

Answer:7m^5 - 3m^3 + 9

Step-by-step explanation: You’d have to remove the brackets, but remember that the second has to have everything multiplied by -1, because there’s a minus sign in front of the second bracket. Then you’d group like terms, then add or subtract. Here’s the step by step

6m^5 + 3 - m^3 - 4m + m^5 - 2m^3 + 4m + 6

2. 6m^5 + m^5 - 2m^3 - m^3 + 4m - 4m + 6 + 3

Subtract or add what’s needed, which would be figures with the same variable and coefficient.

3. 7m^5 - 3m^3 + 9

After this, there’s nothing you can add, since the remaining figures don’t have the same variable.
Hope it’s clear and this wasn’t that long

8 0
2 years ago
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Answer:

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7 0
3 years ago
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Nuetrik [128]

Answer:

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Step-by-step explanation:

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Answer is in the picture:

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