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IgorLugansk [536]
3 years ago
5

During a walk a thin Noah’s time in hours, t, and distance in miles, d, are related by the equation 1/3d = t. A graph of the equ

ation includes the point (12, 4)
1. Identify the independent variable
2. What does the point (12, 4) represent in this situation
3. What point would represent the time it too to walk 7 1/2 miles
Mathematics
1 answer:
Alexandra [31]3 years ago
5 0

Answer: can u give more detail

Step-by-step explanation:

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Last Friday, Erica earned $51 babysitting for 6 hours. At this rate, how many hours would Erica need to babysit in order to earn
zepelin [54]

Answer: 32 hours

Step-by-step explanation: 51/6 = 8.5

So, Erica makes 8.5 dollars per hour. 272/8.5 = 32. Thus, Erica will need 32 hours.

Brainliest?

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3 years ago
60 PTS ASAP! WILL MARK BARAINLEST
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Answer:

d,b,a,c,a

Step-by-step explanation:

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3 0
3 years ago
What would P(A|B) be?
Ipatiy [6.2K]
P(A \cap B) = P(A) \cdot P(B)

so

P(A) = \frac{P(A \cap B)}{P(B)} = \frac{2/3}{3/4} = \frac{8}{9}

also, if A or B happens but not both, you add the chances and subtract the chance that both are happening.

P(A|B) = P(A) + P(B) - P(A \cap B) = \frac{8}{9} +\frac{3}{4} - \frac{2}{3} = \frac{35}{36}

4 0
3 years ago
Which of the following are equivalent to
Anon25 [30]

Answer:

a b

Step-by-step explanation:

6 0
3 years ago
Add an intersection the red light times normally distributed by the mean of three minutes and a standard deviation of .25 minute
Soloha48 [4]

95% of red lights last between 2.5 and 3.5 minutes.

<u>Step-by-step explanation:</u>

In this case,

  • The mean M is 3 and
  • The standard deviation SD is given as 0.25

Assume the bell shaped graph of normal distribution,

The center of the graph is mean which is 3 minutes.

We move one space to the right side of mean ⇒ M + SD

⇒ 3+0.25 = 3.25 minutes.

Again we move one more space to the right of mean ⇒ M + 2SD

⇒ 3 + (0.25×2) = 3.5 minutes.

Similarly,

Move one space to the left side of mean ⇒ M - SD

⇒ 3-0.25 = 2.75 minutes.

Again we move one more space to the left of mean ⇒ M - 2SD

⇒ 3 - (0.25×2) =2.5 minutes.

The questions asks to approximately what percent of red lights last between 2.5 and 3.5 minutes.

Notice 2.5 and 3.5 fall within 2 standard deviations, and that 95% of the data is within 2 standard deviations. (Refer to bell-shaped graph)

Therefore, the percent of  red lights that last between 2.5 and 3.5 minutes is 95%

8 0
4 years ago
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