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3 years ago

8

Sharon walks 11 kilometers during each trip to school. How many trips will Sharon have to make in all to walk a total of 33kilom

eters?

1 answer:

djverab [1.8K]3 years ago

7 0

Answer:

11 kilometres make 1 trip

1 kilometre makes 1/11 trip

33 kilometer makes 1/11*33 = 3 trips

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Give a geometric description of the following system of equations.a. 2x−4y=12 −3x+6y=−15.b. 2x−4y=12 −5x+3y=10.a. 2x−4y=12 −3x+6

Reptile [31]

Answer:

a. No solution, parallel lines.

b. One solution.

Step-by-step explanation:

Given the system of equations:

a. $2x-4y=12$

$-3x+6y=-15$

b. $2x-4y=12$

$-5x+3y=10$

To give a geometric description of the given system of equations.

The geometric description of a system of equations in 2 variables mean the system of equations will represent the number of lines equal to the number of equations in the system given.

i.e.

Number of planes = Number of variables

Number of lines = Number of equations in the system.

Here, we are given 2 variables and 2 equation in each system.

So, they can be represented in the xy-coordinates plane.

And the number of solutions to the system depends on the following condition.

Let the system of equations be:

$A_1x+B_1y+C_1=0\\A_2x+B_2y+C_2=0$

1. One solution:

There will be one solution to the system of equations, If we have:

$\dfrac{A_1}{A_2}\neq\dfrac{B_1}{B_2}$

2. Infinitely Many Solutions: (Identical lines in the system)

$\dfrac{A_1}{A_2}=\dfrac{B_1}{B_2}= \dfrac{C_1}{C_2}$

3. No Solution:(Parallel lines)

$\dfrac{A_1}{A_2}=\dfrac{B_1}{B_2}\neq\dfrac{C_1}{C_2}$

Now, let us discuss the system of equations one by one:

a. $2x-4y=12$ OR $2x-4y-12=0$

$-3x+6y=-15$ OR $-3x+6y+15=0$

$A_1 = 2, B_1 = -4, C_1 = -12\\A_2 = -3, B_2 = 6, C_2= 15$

Here, the ratio:

$\dfrac{A_1}{A_2}=\dfrac{B_1}{B_2} = -\dfrac{2}{3}\\\dfrac{C_1}{C_2} = -\dfrac{4}{5}$

$\dfrac{A_1}{A_2}=\dfrac{B_1}{B_2}\neq\dfrac{C_1}{C_2}$

Therefore, no solution i.e. parallel lines.

b. $2x-4y=12$ OR $2x-4y-12=0$

$-5x+3y=10$ OR $-5x+3y-10=0$

$A_1 = 2, B_1 = -4, C_1 = -12\\A_2 = -5, B_2 = 3, C_2 = -10$

$\dfrac{A_1}{A_2}= -\dfrac{2}{5}\\\dfrac{B_1}{B_2} = -\dfrac{4}{3}\\\dfrac{C_1}{C_2} = -\dfrac{6}{5}$

$\dfrac{A_1}{A_2}\neq\dfrac{B_1}{B_2}$

So, one solution.

Kindly refer to the images attached for the graphical representation of the given system of equations.

6 0

2 years ago

Find (a) PQ to the nearest tenth and (b) the coordinates of the midpoint of __ pq.

lutik1710 [3]

Answer:

a) 5units

b) (4.5, 4)

Step-by-step explanation:

Let the coordinate of P and Q be P(3, 2) and Q(6, 6)

PQ can be gotten using the distance formula;

PQ =√(6-2)²+(6-3)²

PQ = √4²+3²

PQ =√16+9

PQ =√25

PQ = 5units

Midpoint M is expressed as;

M(X, Y) = {(x1+x2)/2, y1+y2/2}

X = x1+x2/2

X = 3+6/2

X= 9/2

X = 4.5

Similarly;

Y = y1+y2/2

Y = 2+6/2

Y = 8/2

Y = 4

Hence the midpoint of PQ is (4.5, 4)

4 0

2 years ago

Which statement must be true to prove | || m?

Yakvenalex [24]

Answer C is correct. If angle 1 + angle 2 = 180 degrees then L is parallel to M.
Co interior angles are only supplementary in parallel lines

6 0

3 years ago

Helpppooo meeeee. !!!!!

Brrunno [24]

Answer:

The looks of the Triangles are different.

Step-by-step explanation:

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3 years ago

To find the quotient of 4.082 and 10,000, move the decimal point in 4.082

Sav [38]

Answer:

move the decimal point in 4.082 4 places to the left

Step-by-step explanation:

i hope this helps :)

3 0

2 years ago