The square has area 8*8=64, the rectangle has area 7*4=28, and the triangle has area 7*6/2=21. Their sum is 64+28+21=113.
∠ ABD = 5(2X+1)
∠ DBC = 3X+6
∠ EBC = Y +135/2
∠ ABD and ∠ DBC are linear pairs
∴ ∠ ABD +∠ DBC = 180
∴ 5(2X+1) + 3X+6 =180
solve for x
∴ x = 13
∴∠ ABD = 5(2X+1) = 5(2*13+1) = 135
∠ DBC = 3x+6 = 3*13+6 = 45
∠ ABD and ∠ EBC are vertical angles
∴ ∠ ABD = ∠ EBC = 135
∴ y +135/2 = 135
∴ y = 135/2
The <span>statements that are true:
--------------------------------------</span><span>
C.) x=13
E.)measure of angle EBC =135
F.) angle DBC and angle EBC are linear pairs
</span>
Answer:
70
Step-by-step explanation:
Complementary angles equal 90 degrees
90 - 20 = 70
I hope this helps!
Answer:
-3
Step-by-step explanation:
2a - 6 = 4a
subtract 2a giving you -6 = 2a
divide by 2 from both sides so that a will be by itself
giving you -6 ÷ 2 = a
-6 ÷ 2 = -3
so a = -3
<u>Q</u><u>uest</u><u>ion</u><u>:</u>
To Simplify:
118 {121÷(11×11)-(-4)-(3-7)}
<u>Solu</u><u>tion</u>:
↠118 {121÷121+4-(-4)}
↠118 {1+4+4}
↠118 {5+4}
↠118{9}
↠118×9
↠1062
▬▬▬▬▬▬▬▬▬▬▬▬
The upper Solution is done by applying BODMAS
<u>Abou</u><u>t</u><u> </u><u>BODMAS</u><u>:</u>
B→ Bracket
O→ Of
D→ Division
M→ Multiplication
A→ Addition
S→ Subtraction
