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Luden [163]
3 years ago
13

Suppose KLMN ~ PQRS. Find the value of x.

Mathematics
1 answer:
arlik [135]3 years ago
3 0

Complete question is attached.

Answer:

B) 8

Step-by-step explanation:

In this question, KLMN ~ PQRS. This means they are similar shapes.

From the image, we could denote that:

KL ~ PQ

LM ~ QR

Given that:

KL = 12

PQ = 30

QR = 20

LM = x

To find x, let's use tge expression:

\frac{KL}{PQ} = \frac{LM}{QR}

=  \frac{12}{30} = \frac{x}{20}

Cross multiplying, we have:

12 * 20 = 30x

240 = 30x

To find x, let's divide both sides by 30.

\frac{240}{30} = \frac{30x}{30}

8 = x

x = 8

The correct option is option B.

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Explanation

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I hope this helps you

5 0
9 months ago
when the wimen sells 90 oranges Rs160 with dicount of 20%,how many oranges she sell by Rs112 with profit of 20%​
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She sold 42 oranges with profit 20%

Step-by-step explanation:

The woman sells 90 oranges by RS.160

This price with discount of 20%

We need to find how many oranges she sell by Rs.112 with profit of 20%​

  • Selling price = cost price - discount ⇒ discount case
  • Selling price = cost price + profit ⇒ profit case

Assume that cost price of an orange is x

∵ She sells 90 oranges with Rs.160

- Find the selling price of 1 orange by dividing 160 by 90

∴ The selling price of an orange = \frac{160}{90}=\frac{16}{9}

∵ She sold them with discount 20%

∵ The cost price of an orange is x

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∵ Discount = 20% × x = \frac{20}{100} × x = 0.2x

- To find the selling price subtract 0.2x from x

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Assume that the number of oranges is y

∵ She sell y oranges for Rs.112 with profit 20%

∵ The cost price of an orange is \frac{20}{9}

- Find 20% of \frac{20}{9}

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- Add \frac{4}{9} to cost price to find the selling price

∴ The selling price of an orange = \frac{20}{9} + \frac{4}{9}

∴ The selling price of an orange = \frac{24}{9}

- To find y divide 112 by selling price of an orange

∵ y = 112 ÷ \frac{24}{9}

∴ y = 42

She sold 42 oranges with profit 20%

Learn more:

You can learn more about percentage in brainly.com/question/12284722

#LearnwithBrainly

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