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photoshop1234 [79]
3 years ago
7

Kate is saving money to take an SAT prep course. So far, she has $180 saved, and she plans to add $17 each month.

Mathematics
1 answer:
Alexus [3.1K]3 years ago
8 0

It will take her 10 weeks to save enough money. 350-180=170 170/17=10 Hope this helps!


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HELP PLZ 5x + -9 + 3x - 20 =
Rama09 [41]
Add like terms. "Like terms" are those with the same constellation of variables.
.. terms with variable x: 5x +3x = (5 +3)x = 8x
.. terms with no variable: -9 -20 = -29

The simplified form is 8x -29.
6 0
3 years ago
Shea wants to wrap a package that is 8 inches by 11 inches by 2 inches. Shea purchased a roll of wrapping paper that is 1 foot w
nekit [7.7K]
First we need to know the surface area of the package:
2(lw) + 2(lh) + 2(wh)
2(8*11) + 2(11*2) + 2(8*2)
2(88) + 2(22) + 2(16)
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Wrapping paper is in feet, so convert it to inches before finding the area.
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6 0
3 years ago
10. Three kinds of teas are worth $4.60 per pound, $5.75 per pound, and $6.50 per pound. They are to be
zepelin [54]

Answer:

The mass of the $4.60/lb tea that should be used in the mixture is 10 lb

The mass of the $5.75/lb tea that should be used in the mixture is 8 lb

The mass of the $6.50/lb tea that should be used in the mixture is 2 lb

Step-by-step explanation:

The parameters of the question are;

The worth of the three teas are

Tea A = $4.60/lb

Tea B = $5.75/lb

Tea C = $6.50/lb

The mass of the mixture of the three teas = 20 lb

The worth of the mixture of the three teas = $5.25 per pound = $5.25/lb

The amount of the $4.60 in the mixture = The sum of the amount of the other two teas

Therefore, given that the mass of the mixture = 20 lb, we have in the mixture;

The mass of tea A + The mass of Tea B + The mass of Tea C = 20 lb

The mass of tea A = The mass of Tea B + The mass of Tea C

Therefore;

The mass of tea A + The mass of tea A = 20 lb

2 × The mass of tea A in the mixture = 20 lb

The mass of tea A in the mixture = 20 lb/2 = 10 lb

The mass of tea A in the mixture = 10 lb

The mass of Tea B + The mass of Tea C = The mass of tea A = 10 lb

The mass of Tea B + The mass of Tea C = 10 lb

The mass of Tea B  = 10 lb - The mass of Tea C

Where the mass of Tea C in the mixture = x, we have;

The mass of Tea B in the mixture = 10 lb - x

The cost of the 10 lb of tea A = 10 × $4.60 = $46.0

The worth of the tea mixture = 20 × $5.25 = $105

The worth of the remaining 10 lb of the mixture comprising of tea A and tea B is given as follows;

The worth of Tea B + The worth of Tea C in the mixture = $105.00 - $46.00 = $59.00

Therefore, we have;

x lb × $6.50/lb + (10 - x) lb × $5.75/lb = $59.00

x × $6.50 - x × $5.75 + $57.50 = $59.00

x × $0.75 = $59.00 -  $57.50 = $1.50

x =  $1.50/$0.75 = 2 lb

∴ The mass of Tea C in the mixture = 2 lb

The mass of Tea B in the mixture = 10 lb - x = 10 lb - 2 lb = 8 lb

The mass of Tea B in the mixture = 8 lb

Therefore, since we have;

Tea A = $4.60/lb

Tea B = $5.75/lb

Tea C = $6.50/lb

The mass of tea A in the mixture = 10 lb

The mass of tea B in the mixture = 8 lb

The mass of tea C in the mixture = 2 lb, we find;

The mass of the $4.60/lb tea that should be used in the mixture = 10 lb

The mass of the $5.75/lb tea that should be used in the mixture = 8 lb

The mass of the $6.50/lb tea that should be used in the mixture = 2 lb.

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3 years ago
What is it quadratic, radical, rational?
mamaluj [8]

Answer:

quadratic formula is ur answer for letter B

3 0
3 years ago
I am giving a lot of points so please be correct and dont answer if you dont know. I will mark brainliest if you are correct
Dennis_Churaev [7]

Answer:

segment GH ≅ segment FH because the tangents that create the segment FG share a common endpoint.

Step-by-step explanation:

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