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2 years ago

Anyone mind helping ?

Mathematics

2 answers:

guajiro [1.7K]2 years ago

8 0

I think it’s 7 seconds

bazaltina [42]2 years ago

3 0

It’s 14 seconds trust me

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A car is traveling at a speed of 25 meters per second what is the cars speed in kilometers per hour how many kilometers will the

Likurg_2 [28]

Answer:

90 km/h
180 km

Step-by-step explanation:

There are 1000 m in 1 km, and 3600 s in 1 h, so the speed conversion is ...

$\dfrac{25\,m}{s}\cdot\dfrac{1\,km}{1000\,m}\cdot\dfrac{3600\,s}{1\,h}=\dfrac{90\,km}{h}$

The car's speed is 90 km/h.

In 2 hours, the car will travel ...

distance = speed · time = (90 km/h)(2 h) = 180 km

7 0

3 years ago

Mr. Schaeffer worked the ticket booth at the football game last Friday night

Afina-wow [57]

And....?

There's not enough info for me to answer.

7 0

3 years ago

The price of a share of stock started the day at $37. During the day it went down $3, up $1, down $7 and up $4. What was the pri

Oksana_A [137]

It started at $37.

It went down $3.
37 - 3 = 34

It went up 1.
34 + 1 = 35

It went down 7.
35 - 7 = 28

It went up 4.
28 + 4 = 32

The price at the end of the day was $32.

4 0

3 years ago

Rob is saving to buy a new MP3 player. For every $14 he earns babysitting, he saves $5. On Saturday, Rob earned $84 babysitting.

Bond [772]

He saved 30 dollars through babysitting. My math is:

84 / 14 = 6

6 x 5 = 30

I hope this helps!

3 0

3 years ago

What does the fundamental theorem of algebra illustrate?

UNO [17]

Answer:

The fundamental theorem of algebra guarantees that a polynomial equation has the same number of complex roots as its degree.

Step-by-step explanation:

The fundamental theorem of algebra guarantees that a polynomial equation has the same number of complex roots as its degree.

We have to find the roots of this given equation.

If a quadratic equation is of the form $ax^{2}+bx +c=0$

Its roots are $\frac{-b+\sqrt{b^{2}-4ac } }{2a}$ and $\frac{-b-\sqrt{b^{2}-4ac } }{2a}$

Here the given equation is $2x^{2}-4x-1$ = 0

a = 2

b = -4

c = -1

If the roots are $x_{1} and x_{2}$ , then

$x_{1}$ = $\frac{-2+\sqrt{(-4)^{2}-4\times 2\times (-1)}}{2\times 2}$

= $\frac{4 +\sqrt{24}}{4}$

= $\frac{2+\sqrt{6} }{2}$

$x_{2}$ = $\frac{-2-\sqrt{(-4)^{2}-4\times 2\times (-1)}}{2\times 2}$

= $\frac{4 +\sqrt{8}}{4}$

= $\frac{2-\sqrt{6} }{2}$

These are the two roots of the equation.

6 0

2 years ago