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Marina86 [1]
3 years ago
8

The original price of a sweatshirt is $45.00. If the sweatshirt is marked down 20% , what is the new price?

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
4 0

Answer: 36

Step-by-step explanation:

The 100% of the sweater is 45, we multiply 45 per 20 divided by 100, that will give you 9, you want to rest 45-20%

45-9=36

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Given that f(x)=x^2+3x-28f(x)=x
spayn [35]

9514 1404 393

Answer:

  x^2 +4x -21

Step-by-step explanation:

Substitute the given expressions and simplify.

  f(x) + g(x)

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6 0
3 years ago
According to the US Bureau of labor statistics, 7% of US female workers between 16 and 24 years old are paid at the minimum wage
vladimir1956 [14]

Answer:

The Null Hypothesis is  H_o:k_o = 0.07

The alternative hypothesis is  H_a :k_o \ne 0.07

Decision rule

    If the test staistics is  greater than the critical value of significance level then H_o is accepted else H_o  is rejected

With the above in mind

       The critical value of the significance level which is obtained from the table is

     t_{0.05} = 1.645

Now since the critical value of significance level is greater than the test  staistics then the null hypothesis will be rejected

Conclusion

The information is not enough to back the claim that state differs from the nation

Step-by-step explanation:

From the question we are told that

The percentage of US female workers paid at the minimum wage or less is  k_o = 7% = 0.07

  The sample size is  n =  500

    The number paid minimum wage or less is  x = 42

    The significance level is \alpha  =5%  = 0.05

Now the probability of getting a US female workers paid at the minimum wage or less is mathematically represented as

         \= k = \frac{x}{n}

substituting value

        \= k = \frac{42}{500}

        \= k = 0.084

The Null Hypothesis is  H_o:k_o = 0.07

The alternative hypothesis is  H_a :k_o \ne 0.07

Generally the test statistics is mathematically evaluated as

        z =  \frac{\=  k  - k_o}{\sqrt{\frac{k_o(1-k_o)}{n} } }

substituting value

      z =  \frac{0.084  - 0.07}{\sqrt{\frac{0.07 (1-0.07)}{500} } }

     z =  1.23

Now the Decision rule is stated as  

        If the test staistics is  greater than the critical value of significance level then H_o is accepted else H_o  is rejected

With the above in mind

       The critical value of the significance level which is obtained from the table is

     t_{0.05} = 1.645

Now since the critical value of significance level is greater than the test  staistics then the null hypothesis will be rejected

   So the conclusion will be

   The information is not enough to back the claim that state differs from the nation

 

4 0
3 years ago
For the data set { -4 , 8 , 4 , 0 , 7 , -2 , -5 , 6 }, the range is
statuscvo [17]

The interquartile range is 9.5.

Hope this helps!!!!!!

Please give me brainliest!!!!!!!!

3 0
3 years ago
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