Question

What is the x-intercept of the line containing the points (–6, 10) and (12, –2)?

Answer 1

Point-point equation
$\frac{y-y_{1}}{x-x_{1}} = \frac{y_{2}-y_{1}}{x_{2}-x_{1}} , \frac{y-10}{x+6} = \frac{-2-10}{12+6} , \frac{y-10}{x+6} = \frac{-12}{18} , \frac{y-10}{x+6} = \frac{-2}{3} x-intercept is the point when y=0, we can substitute y with 0.$

$\frac{-10}{x+6} = -\frac{2}{3} , \frac{10}{x+6} = \frac{2}{3} 10*3=2(x+6) 30=2x+12 2x=18 x=9, x-intercept (9.0)$