All categories

3 years ago

Lines A and B are parallel

Mathematics

1 answer:

Alinara [238K]3 years ago

4 0

Answer:

your answer is

C ) 36°
I think that is right answer
please mark in brain list.

Explain:

180/5= 36

36×4= 144

180-144= 36 .

You might be interested in

HELP ME FIND THE SLOPE

Tomtit [17]

Answer:

$m=\frac{-5}{2}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Slope Formula: $m=\frac{y_2-y_1}{x_2-x_1}$

Step-by-step explanation:

Step 1: Define

Choose any 2 points from the chart.

Point (-6, 11)

Point (-2, 1)

Step 2: Find slope m

Substitute: $m=\frac{1-11}{-2+6}$
Subtract/Add: $m=\frac{-10}{4}$
Simplify: $m=\frac{-5}{2}$

4 0

3 years ago

If P and Q are two sets then n( P-Q) means ?

Lapatulllka [165]

$\huge{\mathbb{ \tt{ANSWER}}}$

I shall use the symbol U for union

^ for intersection

~ for complement

The property of set subtraction states that for any sets X and Y, X-Y = X ^ Y~

That is in words, X throw away Y is the same as the intersection of X and the complement of Y

or X and anything NOT in Y

At the SET level, the proof looks like this:

(P-Q) U (Q-P) = « given

(P^Q~) U (Q ^ P~) = « property of set subtraction

(P U Q) ^ (P U P~) ^ (Q~ U Q) ^ (Q~ U P~) = « distributive property

(P u Q) ^ (Q~ U P~) = « Union of any set with it's complement is the universal

set which gets dropped by any intersection of a non-universal set

(P u Q ) ^ (Q ^ P)~ = « De Morgan's Law

(P u Q) - (Q ^ P) = « property of set subtraction

(P u Q) - (P ^ Q) « commutative property

At the ELEMENT level, the proof looks like this:

» Proves left side is subset of right side

If x is in (P-Q) U (Q-P) then x is in (P-Q) OR x is in (Q-P)

If x is in P-Q then x is in P but not in Q.

Then X is in P U Q.

Since x is not in Q, x is NOT in P ^ Q

Hence x is in P U Q but NOT in P^Q, which

means it is an element if (P U Q) - (P ^ Q)

Therefore x is an element of the set defined by the right side, which means (P-Q) U (Q-P) is a subset of (P U Q) - (P ^ Q)

« proves right side is subset of the left side

If x is an element of (P U Q) - (P ^ Q) then

x is in (P U Q) but NOT in (P^Q)

Since x is in P U Q, x is in P OR x is in Q.

Since x is NOT in (P^Q) then x is NOT in BOTH P and Q.

Hence x is in either P or Q but not both.

If x is in P, then x is not in Q, so x is in P-Q.

Therefore x is in (P-Q) U (Q-P).if x is in Q, then x is not in P, so x is in Q-P.Therefore x is in (Q-P) U (P-Q).There x is an element of set defined by the left side, which menas (P u Q)-(P ^Q) is a subset of (P-Q) U (Q-P).

#CarryOnLearning

#LetsEnjoyTheSummer

8 0

3 years ago

How to check your work on a division problem.

Rus_ich [418]

Answer:

By checking it with multiplication

Step-by-step explanation:

You can use multiplication to check your division answer this way.

Do the division problem.

Multiply the quotient times the divisor.

If there is a remainder, add it to the multiplication product.

Compare this answer to the dividend. They should be the same number (630 = 630).

4 0

3 years ago

Read 2 more answers

2. Candles normally cost £6 each.

saw5 [17]

Answer: candies are us has a better offer

Step-by-step explanation:

for the candies r us website, the price of the candies is 30*6 then times 0.8=$144

and for waxz, if you buy 3 get 1 free, then you at least have to buy 3 candies 9 times, and that would be 18*9 which equals 162, which is more expensive then waxz

hope this helps!

please make me brainliest! thanks!

8 0

3 years ago

Parallelogram ABCD is dilated to form parallelogram WXYZ. What corresponding side is proportional to segment AD? Type the answer

Reika [66]

Answer: WZ

The sequence ABCD has AD as the first and last letters of that sequence, so this pattern applies to WXYZ as well to pull out WZ. Angle A pairs up with angle W because they are both the first letters of the sequences. These angles are congruent from the fact that the parallelograms are similar. The same can be said for angle D and angle Z.

note: WZ is the same as ZW. The order doesn't matter when it comes to labeling segments based on endpoints.

6 0

3 years ago