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coldgirl [10]
3 years ago
5

1) Solve 2 + 7x + 12 = 0 using factoring and the zero product property.

Mathematics
1 answer:
Kazeer [188]3 years ago
4 0

Answer:

7x+14=0, 7x=-14, x= -2

Step-by-step explanation:

add like terms, then get x on one side, number on the other, then divide both sides by 7

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What are the scale factor of ABC dilated to XYZ plz help
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<h3>Answer:  B) 2/3</h3>

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Explanation:

The order is important for ABC and XYZ so we can see what letters pair up.

  • A pairs with X since they are the first letters
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  • C pairs with Z since they are the third letters

Based on that, we can see that AB pairs with XY as they are the first two letters of ABC and XYZ respectively.

Divide the length XY over AB and reduce

XY/AB = 10/15 = 2/3

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XZ/AC = 14/21 = 2/3

and we get the same ratio

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Step-by-step explanation:

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1439<br> 31<br> a. 71.9<br> b. 62<br> c. 56.3<br> d. 42.4<br> Solve for x
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Step-by-step explanation:

3 0
2 years ago
M is a degree 3 polynomial with m ( 0 ) = 53.12 and zeros − 4 and 4 i . Find an equation for m with only real coefficients (i.E.
Nitella [24]

Answer:

Therefore the required polynomial is

M(x)=0.83(x³+4x²+16x+64)

Step-by-step explanation:

Given that M is a polynomial of degree 3.

So, it has three zeros.

Let the polynomial be

M(x) =a(x-p)(x-q)(x-r)

The two zeros of the polynomial are -4 and 4i.

Since 4i is a complex number. Then the conjugate of 4i is also a zero of the polynomial i.e -4i.

Then,

M(x)= a{x-(-4)}(x-4i){x-(-4i)}

      =a(x+4)(x-4i)(x+4i)

      =a(x+4){x²-(4i)²}      [ applying the formula (a+b)(a-b)=a²-b²]

      =a(x+4)(x²-16i²)

      =a(x+4)(x²+16)      [∵i² = -1]

      =a(x³+4x²+16x+64)

Again given that M(0)= 53.12 . Putting x=0 in the polynomial

53.12 =a(0+4.0+16.0+64)

\Rightarrow a = \frac{53.12}{64}

      =0.83

Therefore the required polynomial is

M(x)=0.83(x³+4x²+16x+64)

5 0
3 years ago
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